In: Physics
A straight wire carries a 12-A current eastward and a second straight wire carries a 14-A current westward. The wires are separated by a distance of 42 cm. The force on a 6.4 m length of one of the wires is..
8.0 × 10-5 N. |
8.0 × 10-7 N. |
5.1 × 10-6 N. |
5.1 × 10-4 N. |
not possible to determine with the information given. |
The answer is : F =
Given that,
Current carried by first wire,
= 12 A
Current carried by second wire,
= 14 A
Distance between 2 wires, r= 42 cm = 0.42 m
Lenght of segment of 1 of the wire on which force is to be calculated , L = 6.4 m
Solution
The force between 2 current carrying conductor is given by the equation,
Where
is the magnetic permeability of vacuum space,
T.m/A.
By substituting the above values in the equation , we can
calculate force, F
Therefore Force exerted on 6.4 m length of one wire,
Option (4) F
=
This force exerted between the 2 wires is repulsive because the direction of current in 1st wire is opposite to the direction of current in 2nd wire.
Explanation for the equation of force,