Question

A straight vertical wire carries a current of 1.45 A downward in a region between the poles of a large electromagnet where the field strength is 0.570 T and is horizontal.

1)What are the magnitude of the magnetic force on a 1.60 cm section of this wire if the magnetic-field direction is toward the east?

2)What are the magnitude of the magnetic force on a 1.60 cm section of this wire if the magnetic-field direction is toward the south?

3) What are the direction of the magnetic force on a 1.60 cm section of this wire if the magnetic-field direction is 30.0 o south of west ?

4) What are the magnitude of the magnetic force on a 1.60 cm section of this wire if the magnetic-field direction is 30.0 o south of west ?

Answer 1

1.)

The Force on the conductor = Flux Density x Current x Active Length of Conductor
Force = 0.570 T x 1.45 A x 0.016 m
= 0.013224 N
Using Fleming's Left Hand Rule [ first finger is the direction of magnetic flux, second finger is the direction of the current in the conductor and thumb is direction of the force on the conductor ] the wire will be deflected to the South relative to the West to East magnetic field.

2.)

F = IL X B, where X signifies a cross product. For direction, using the right-hand rule, point your index finger along IL and middle finger along B; then your thumb points roughly along F.
F points west.
|F| = ILB = 0.013224 N.

3.)

F = IL X B, where X signifies a cross product. For direction, using the right-hand rule, point your index finger along IL and middle finger along B; then your thumb points roughly along F.

F points up

4,) Its magnitude = ILBsin(30 d) = 6.612 * 10^-3 N.