Question

A straight, vertical wire carries a current of 1.27 A downward in a region between the poles of a large superconducting electromagnet, where the magnetic field has a magnitude of B = 0.567 T and is horizontal.

Part A

What is the magnitude of the magnetic force on a section of the wire with a length of 1.00 cm that is in this uniform magnetic field, if the magnetic field direction is east? (Unit N)

Part B

What is the direction of the magnetic force on a section of the wire with a length of 1.00 that is in this uniform magnetic field, if the magnetic field direction is east?

south

north

west

east Part C What is the magnitude of the magnetic force on a section of the wire with a length of 1.00 cm that is in this uniform magnetic field, if the magnetic field direction is south? (Unit N) Part D What is the direction of the magnetic force on a section of the wire with a length of 1.00 cm that is in this uniform magnetic field, if the magnetic field direction is south? What is the direction of the magnetic force on a section of the wire with a length of 1.00 that is in this uniform magnetic field, if the magnetic field direction is south? south north west east Part E What is the magnitude of the magnetic force on a section of the wire with a length of 1.00 cm that is in this uniform magnetic field, if the magnetic field direction is 26.0 ? south of west? (Unit N) Part F What angle will the magnetic force on this segment of wire make relative to the north, if the magnetic field direction is 26.0 ? south of west? (Unit ? west of north )

Answer 1

Part A

magnitude of the magnetic force

F = B*i*L*sin

F = 0.567*1.27*1*10^-2*sin90^o

F = 0.0072 N

Part B

to find the direction of the magnetic force we use the Right hand rule-2

The direction of the current is downward and magnetic field direction is toward the east .from the right hand rule

the direction of the force is toward the south .

PartC

magnitude of the magnetic force

F = B*i*L*sin

F = 0.567*1.27*1*10^-2*sin90^o

F = 0.0072 N

PartD

The direction of the current is downward and magnetic field direction is toward the south ,from the right hand rule

the direction of the force is toward the west .

PartE

magnitude of the magnetic force

F = B*i*L*sin

F = 0.567*1.27*1*10^-2*sin90^o

F = 0.0072 N

PartF

The direction of the current is downward and magnetic field direction is 26^o south of west ,from right hand rule-2 the direction of force is 64^o North of west.