In: Statistics and Probability
Assume that females have pulse rates that are normally distributed with a mean of μ=74.0beats per minute and a standard deviation of 5σ=12.5 beats per minute. Complete parts (a) through (c) below.
a) If 1 adult female is randomly selected, find the probability that her pulse rate is less than 80 beats per minute.
b) If 44 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 80 beats per minute.
Solution :
Given that ,
mean = = 74.0
standard deviation = = 12.5
(A)n = 1
= 74.0
= / n = 12.5 / 1=12.5
P( < 80) = P[( - ) / < (80 -74.0) / 12.5]
= P(z <0.48 )
Using z table
= 0.6844
probability= 0.6844
(B)
n =44
= 74.0
= / n = 12.5 / 44=1.8845
P( < 80) = P[( - ) / < (80 -74.0) / 1.8845]
= P(z <3.18 )
Using z table
= 0.9993
probability= 0.9993