Question

In: Economics

The following table lists a portion of Major League Baseball’s (MLB’s) leading pitchers, each pitcher’s salary...

The following table lists a portion of Major League Baseball’s (MLB’s) leading pitchers, each pitcher’s salary (In $ millions), and earned run average (ERA) for 2008.

a-1. Estimate the model: Salary = β0 + β1ERA + ε. (Negative values should be indicated by a minus sign. Enter your answers, in millions, rounded to 2 decimal places.)Click here for the Excel Data File

Salary ERA
J. Santana 17.0 2.25
C. Lee 2.0 2.37
T. Lincecum 0.1 2.57
C. Sabathia 10.0 2.11
R. Halladay 7.0 2.52
J. Peavy 5.7 2.77
D. Matsuzaka 6.7 2.44
R. Dempster 6.6 2.89
B. Sheets 11.5 2.90
C. Hamels 0.3 2.91

Salaryˆ=Salary^=    +  ERA

a-2. Interpret the coefficient of ERA.

  • A one-unit increase in ERA, predicted salary decreases by $6.37 million.

  • A one-unit increase in ERA, predicted salary increases by $6.37 million.

  • A one-unit increase in ERA, predicted salary decreases by $16.70 million.

  • A one-unit increase in ERA, predicted salary increases by $16.70 million.

b. Use the estimated model to predict salary for each player, given his ERA. For example, use the sample regression equation to predict the salary for J. Santana with ERA = 2.25. (Round coefficient estimates to at least 4 decimal places and final answers, in millions, to 2 decimal places.)

c. Derive the corresponding residuals. (Negative values should be indicated by a minus sign. Round coefficient estimates to at least 4 decimal places and final answers, in millions, to 2 decimal places.)

Solutions

Expert Solution

a-1. Salary = 23.0715-6.3667*ERA

we need to use regression function in excel data analysis to get the results as below:

SUMMARY OUTPUT

Regression Statistics

Multiple R

0.3480

R Square

0.1211

Adjusted R Square

0.0113

Standard Error

5.2169

Observations

10

ANOVA

df

SS

MS

F

Significance F

Regression

1

30.0044

30.0044

1.1025

0.3244

Residual

8

217.7246

27.2156

Total

9

247.7290

Coefficients

Standard Error

t Stat

P-value

Lower 95%

Upper 95%

Intercept

23.0715

15.6886

1.4706

0.1796

-13.1066

59.2496

ERA

-6.3667

6.0636

-1.0500

0.3244

-20.3494

7.6160

a-2. Option 1
From the above table we can observe that the coefficient is negative indicates about the negative relationship, hence one unit increase in ERA decreases salary by $ 6.37 million

b.

Salary

ERA

Forecast

17

2.25

23.0715-6.3667*2.25 = 8.75

2

2.37

23.0715-6.3667*2.37 = 7.98

0.1

2.57

23.0715-6.3667*2.57 = 6.71

10

2.11

23.0715-6.3667*2.11 = 9.64

7

2.52

23.0715-6.3667*2.52=7.03

5.7

2.77

23.0715-6.3667*2.77 =5.44

6.7

2.44

23.0715-6.3667*2.44=7.54

6.6

2.89

23.0715-6.3667*2.89=4.67

11.5

2.9

23.0715-6.3667*2.90=4.61

0.3

2.91

23.0715-6.3667*2.91=4.54

c.

Salary

ERA

Forecast

Residuals = Actual-Forecast

17

2.25

8.75

=17-8.75 = 8.25

2

2.37

7.98

=2-7.98 = -5.98

0.1

2.57

6.71

=0.1-6.71 =-6.61

10

2.11

9.64

=10-9.64 = 0.36

7

2.52

7.03

=7-7.03 = -0.03

5.7

2.77

5.44

=5.7-5.44 = 0.26

6.7

2.44

7.54

= 6.7-7.54 = -0.84

6.6

2.89

4.67

= 6.6-4.67 = 1.93

11.5

2.9

4.61

=11.5-4.61 = 6.89

0.3

2.91

4.54

=0.3-4.54 = -4.24


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