In: Finance
Wheeling-Pittsburgh Steel Company installed a new machine at a cost of $285000. The expected salvage value of this machine was $50000 after 10 years. During this 10 years, the annual revenue was $52000.
a)
Annual worth of project = -285000*(A/P,0.12,10) + 52000 + 50000*(A/F,0.12,10)
Let us calculate the interest factors
Annual worth of project = -285000*0.176984 + 52000 + 50000*0.056984 = 4408.76
AW is positive. We can say that the company was able to recover the investment at 12% per year return.
b)
AW of operating cost = -10000-1000*(P/G,0.12,10)*(A/P,0.12,10)
AW of operating cost = -10000-1000*20.254089*0.176984 = -$13584.65
Annual worth of project = 4408.76-13584.65 = -$9175.89
AW of project is negative
a. AW is positive. We can say that the company was able to recover the investment at 12% per year return.
b. AW of project is negative