In: Statistics and Probability
Find the 95% confidence interval for the slope in each of the following settings. (Round your answers to three decimal places.)
a) n = 20, ŷ = 27.5 + 1.8x, and SEb1 = 0.85
b) n = 30, ŷ = 30.6 + 2.1x, and SEb1 = 1.05
c) n = 100, ŷ = 29.5 + 2.1x, and SEb1 = 1.05
Here, we need to find the 95% confidence interval for the slope
we know that the least square regression line is as follows,
where,
= dependent outcome variable and x is the independent variable
is the intercept and
is the slope parameter
(A)
we have given that
n= 20
i.e.
=intercept=27.5 and
=slope=1.8
=Standard
error of slope = 0.85
Now we cab find the 95% confidence interval for the
slope
The formula is as follows
where b1 is the slope
first, we can find the critical value
Degrees of freedom = n-2 = 20 -2 =18
c=confidnece level =0.95
=
level of significance= 1-c =1-0.95=0.05
this 95% CI is two tailed
t-critical = 2.101 Using Excel software =TINV(probablity =0.05, D.F=18)
Now,
The 95% CI is (0.014, 1.814)
(B)
we have given that
n= 30
i.e.
=intercept=30.6 and
=slope=2.1
=Standard
error of slope = 1.05
Now we cab find the 95% confidence interval for the
slope
The formula is as follows
where b1 is the slope
first, we can find the critical value
Degrees of freedom = n-2 = 30 -2 =28
c=confidnece level =0.95
=
level of significance= 1-c =1-0.95=0.05
this 95% CI is two tailed
t-critical =2.048 Using Excel software =TINV(probablity =0.05, D.F=28)
Now,
The 95% CI is (-0.050, 4.250)
(C)
we have given that
n= 100
i.e.
=intercept=29.5 and
=slope=2.1
=Standard
error of slope = 1.05
Now we cab find the 95% confidence interval for the
slope
The formula is as follows
where b1 is the slope
first, we can find the critical value
Degrees of freedom = n-2 = 100 -2 =98
c=confidnece level =0.95
=
level of significance= 1-c =1-0.95=0.05
this 95% CI is two tailed
t-critical = 1.984 Using Excel software =TINV(probablity =0.05, D.F=98)
Now,
The 95% CI is (0.016, 4.184)