In: Statistics and Probability
Find the necessary confidence interval for a population mean μ for the following values. (Round your answers to two decimal places.)
α = 0.05, n = 83, x = 66.4, s2 = 2.58
? to ?
Solution :
Given that,
Point estimate = sample mean = = 66.4
s2 = 2.58
sample standard deviation = s = s2 = 2.58 = 1.61
sample size = n = 83
Degrees of freedom = df = n - 1 = 83 - 1 = 82
At 95% confidence level
= 1 - 95%
=1 - 0.95 =0.05
/2
= 0.025
t/2,df
= t0.025,82 = 1.989
Margin of error = E = t/2,df * (s /n)
= 1.989 * ( 1.61/ 83)
Margin of error = E = 0.35
The 95% confidence interval estimate of the population mean is,
± E
= 66.4 ± 0.35
= ( 66.05, 66.75 )