Question
In: Statistics and Probability
Historical Data shows that the diameter of current piston is a normally distributed random variable with...
Historical Data shows that the diameter of current piston is a
normally distributed random variable with mean of 12 centimeters
and a standar deviation of 0.06 centimeters.
1.if we use 46 ramdomly selected rings and calculate Xbar
(average) , what is the probability of having and Xbar greater than
12.01 centimeters? Use original value of standard deviation.
2. Assume you take 40 rings and put them side by side in a
line, what is the probability that the length of the line will
exceed 490 centimeters? Use original value of standard
deviation.
Solutions
orchestra answered 2 years agoRelated Solutions
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The inside diameter of a piston ring is normally distributed with a mean of 10 cm...
The inside diameter of a piston ring
is normally distributed with a mean of 10 cm and a standard
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What is the probability that a piston ring will have an inside
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What is the probability that a piston ring will have an inside
diameter between 9.94 and 10.045 cm?
What proportion of rings will have inside diameters exceeding
10.066 cm?
Suppose that five piston rings are randomly selected. What is
the...
The inside diameter of a randomly selected piston ring is a random variable with mean value...
The inside diameter of a randomly selected piston ring is a
random variable with mean value 11 cm and standard deviation 0.06
cm.
(a) If
X
is the sample mean diameter for a random sample of n =
16 rings, where is the sampling distribution of
X
centered and what is the standard deviation of the
X
distribution? (Enter your standard deviation to five decimal
places.)
center
cm
standard deviation
cm
(b) Answer the questions posed in part (a) for...
The inside diameter of a randomly selected piston ring is a random variable with mean value...
The inside diameter of a randomly selected piston ring is a
random variable with mean value 15 cm and standard deviation 0.07
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answers to four decimal places.)
(a) Calculate
P(14.99 ≤ X ≤ 15.01)
when n = 16.
P(14.99 ≤ X ≤ 15.01)
=
(b) How likely is it that the sample mean diameter exceeds 15.01
when n = 25?
P(X ≥ 15.01)
=
Data set : Data Set G: Assume the population values are normally distributed. Random variable: x...
Data set :
Data Set G: Assume the population values are normally
distributed.
Random variable: x = weight of border collie in pounds
sample size = 25
34.1
40.8
36.0
34.9
35.6
43.4
35.4
29.3
33.3
37.8
35.8
37.4
39.0
38.6
33.9
36.5
37.2
37.6
37.3
37.7
34.9
33.2
36.2
33.5
36.9
1. Choose another confidence level similar to one found in the
homework (do not use the
confidence level from the posted example). Based on the second
confidence level,...
For a random variable that is normally distributed, with μ = 80 and σ = 10,...
For a random variable that is normally distributed, with μ = 80
and σ = 10, determine the probability that a simple random sample
of 25 items will have a mean between 78 and 85?
a.
83.51%
b.
15.87%
c.
99.38%
d.
84.13%
5. A random variable is not normally distributed, but it is mound shaped. It has a...
5. A random variable is not normally distributed, but it
is mound shaped. It has a mean of 14 and a standard deviation of 3.
(Section 6.5)
a.) If you take a sample of size 10, can you say what
the shape of the sampling
distribution for the sample mean is? Why?
b.) For a sample of size 10, state the mean of the
sample mean and the standard deviation of the sample
mean.
c.) If you take a sample...
X is a random variable which is normally distributed with a mean of 99.01 and a...
X is a random variable which is normally distributed with a mean
of 99.01 and a standard deviation of 15.56. Use the Excel function
NORMINV to determine the required value of Xo to two decimal
places. Give your answer in the form xx.xx. P(X < Xo) =
0.0344
Answer:
A random variable is normally distributed with a mean of 24 and a standard deviation of...
A random variable is normally distributed with a mean of 24 and
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a. What value will be exceeded 5% of the time?
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d. What value will 10% of the observations be...
The weight of a small Starbucks coffee is a normally distributed random variable with a mean...
The weight of a small Starbucks coffee is a normally distributed
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highest 30 percent
middle 70 percent
highest 90 percent
lowest 20 percent
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