In: Math
A knitting shop orders yarn from three suppliers in
Toronto, Montreal, and Ottawa. One month the shop ordered total of
101 units of yarn from
these suppliers. The delivery costs were $80, $50, and $62 per unit
for the orders from Toronto, Montreal, and Ottawa, respectively,
with total delivery costs of $6100. The shop ordered the same
amount from Toronto and Ottawa. How many units were ordered from
each supplier?
Let Toronto and ottawa equal x and let Montreal equal M
shipping cost
80x+62x+50M=6100
solve for x
142x+50M=6100
x=(6100-50M)/142 --------------Eq(i)
Lets make an Expression for M
if they bought 101 units then
M+x+x=101
M+2x=101
M=101-2x
subtitute in above Equation---------(i)
x=(6100-50(101-2x)) / 142
x=(6100-5050+100x) / 142
142x=(1050+100x)
42x=1050
x=25
They bought 25 units each from Toronto and ottawa
From before
x+x+M=101
2x+M=101
2(25)+M=101
50+M=101
M=51
They bought 51 units from Montreal
[ Check it:25+25+51=101]
80(25)+50(51)+62(25)=6100
2000+2550+1550=6100
Therefore 6100=6100