At time t = 11.5 sec, a particle of mass M = 5 kg is at...

At time t = 11.5 sec, a particle of mass M = 5 kg is at the position (x,y,z) = (4,4,6) m and has velocity (2,1,-2) m/s.

1) What is the x component of the particle's angular momentum about the origin?

Answer: -70 kg m²

2) What is the y component of the particle's angular momentum about the origin?

Answer:100 kg m²

3) What is the z component of the particle's angular momentum about the origin?

Answer: -20 kg m²

4) Now an identical particle is placed at (x,y,z) = (-4,-4,-6) m, with velocity (-2,-1,2) m/s. What is the x component of the pair's total angular momentum about the origin?

Answer: -140 kg m²

5) What is the y component of the pair's total angular momentum about the origin?

Answer: 200 kg m²

6) What is the z component of the pairs's total angular momentum about the origin?

Answer: -40 kg m²

7) Finally a thin rod of mass 11 kg is added between the two particles Since the particles are moving perpendicular to the line separating them and in opposite directions (you should convince yourself that this is true), then the particles + rod system rotates about its center of mass. What the angular frequency of rotation of the rod + particles system? (Note: The particles are moving perpendicular to the line separating them and in opposite directions (you should convince yourself that this is true), then the particles + rod system rotates about its center of mass.)

Answer: 0.364 rad/sec

8) What is the magnitude of the total angular momentum of the system (particles plus rod)?

Please solve number 8!

Solutions

Expert Solution

genius_generous answered 1 year ago

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