Question

In: Physics

At time t = 11.5 sec, a particle of mass M = 5 kg is at...

At time t = 11.5 sec, a particle of mass M = 5 kg is at the position (x,y,z) = (4,4,6) m and has velocity (2,1,-2) m/s.

1) What is the x component of the particle's angular momentum about the origin?

Answer: -70 kg m2

2) What is the y component of the particle's angular momentum about the origin?

Answer:100 kg m2

3) What is the z component of the particle's angular momentum about the origin?

Answer: -20 kg m2

4) Now an identical particle is placed at (x,y,z) = (-4,-4,-6) m, with velocity (-2,-1,2) m/s. What is the x component of the pair's total angular momentum about the origin?

Answer: -140 kg m2

5) What is the y component of the pair's total angular momentum about the origin?

Answer: 200 kg m2

6) What is the z component of the pairs's total angular momentum about the origin?

Answer: -40 kg m2

7) Finally a thin rod of mass 11 kg is added between the two particles Since the particles are moving perpendicular to the line separating them and in opposite directions (you should convince yourself that this is true), then the particles + rod system rotates about its center of mass. What the angular frequency of rotation of the rod + particles system? (Note: The particles are moving perpendicular to the line separating them and in opposite directions (you should convince yourself that this is true), then the particles + rod system rotates about its center of mass.)

Answer: 0.364 rad/sec

8) What is the magnitude of the total angular momentum of the system (particles plus rod)?

Please solve number 8!

Solutions

Expert Solution

genius_generous answered 2 years ago
Next > < Previous

Related Solutions

At time t = 9 sec, a particle of mass M = 3 kg is at...
At time t = 9 sec, a particle of mass M = 3 kg is at the position (x,y,z) = (4,4,6) m and has velocity (2,1,-2) m/s. 1) What is the x component of the particle's angular momentum about the origin? 2) What is the y component of the particle's angular momentum about the origin? 3) What is the z component of the particle's angular momentum about the origin? 4) Now an identical particle is placed at (x,y,z) = (-4,-4,-6)...
Suspended Mass (kg) Weight of Suspended Mass (mass x 9.8 m/s2), Newtons Time (sec) Average Time...
Suspended Mass (kg) Weight of Suspended Mass (mass x 9.8 m/s2), Newtons Time (sec) Average Time Average Time2 d (m) 2d (m) Acceleration = 2d/t2 3 Washers 0.0143 0.14N Trial 1: 1.76 1.84 s 0.34 m/s2 0.6m 1.2m 0.35 m/s2 Trial 2: 1.86 Trial 3: 1.90 4 Washers 0.0191 0.19N Trial 1: 1.50 1.1 s 1.21 s2 0.6m 1.2m 0.99 m/s2 Trial 2: 1.50 Trial 3: 1.45 5 Washers 0.025 0.25N Trial 1: 1.23 1.23 s 1.51 s2 0.6m 1.2m...
A particle of mass 2.00 kg moves with position r(t) = x(t) i + y(t) j...
A particle of mass 2.00 kg moves with position r(t) = x(t) i + y(t) j where x(t) = 10t2 and y(t) = -3t + 2, with x and y in meters and t in seconds. (a) Find the momentum of the particle at time t = 1.00 s. (b) Find the angular momentum about the origin at time t = 3.00 s.
A particle of mass 2.00 kg moves with position r(t) = x(t) i + y(t) j...
A particle of mass 2.00 kg moves with position r(t) = x(t) i + y(t) j where x(t) = 10t2 and y(t) = -3t + 2, with x and y in meters and t in seconds. (a) Find the momentum of the particle at time t = 1.00 s. (b) Find the angular momentum about the origin at time t = 3.00 s.
A bullet of mass m=20 gr is fired into a block of mass M=5 kg initially...
A bullet of mass m=20 gr is fired into a block of mass M=5 kg initially at rest at the edge of a frictionless table of height h=0.90 m. The bullet remains in the block and the block lands a distance d=0.68 m from the bottom of the table. Picture1 a)Determine the initial velocity of the bullet. vi= m/s b) Determine the loss of kinetic Energy during the collision. ΔK = J.
A bullet with a mass m b = 11.5 g is fired into a block of...
A bullet with a mass m b = 11.5 g is fired into a block of wood at velocity v b = 265 m/s. The block is attached to a spring that has a spring constant k of 205 N/m. The block and bullet continue to move, compressing the spring by 35.0 cm before the whole system momentarily comes to a stop. Assuming that the surface on which the block is resting is frictionless, determine the mass of the wooden...
A charged particle of mass m = 7.3X10-8 kg, moving with constant velocity in the y-direction...
A charged particle of mass m = 7.3X10-8 kg, moving with constant velocity in the y-direction enters a region containing a constant magnetic field B = 1.8T aligned with the positive z-axis as shown. The particle enters the region at (x,y) = (0.5 m, 0) and leaves the region at (x,y) = 0, 0.5 m a time t = 463 μs after it entered the region. 1. With what speed v did the particle enter the region containing the magnetic...
8) 3 kg mass moving with 10 m/s in the x-direction hits a 5 kg mass...
8) 3 kg mass moving with 10 m/s in the x-direction hits a 5 kg mass at rest. After the collision 3 kg is deflected by 30 degree while the 5 kg is deflected by 45 degrees. a) Draw a diagram for the initial and final motion including the directions of the velocities b) Find the final velocities of each mass c) Determine if the collision is elastic or not. d) Qualitatively, show the direction of the impulse (or the...
An unstable particle with a mass equal to 3.34x10^-27 kg is initially at rest. The particle...
An unstable particle with a mass equal to 3.34x10^-27 kg is initially at rest. The particle decays into two fragments that fly off with velocities of 0.981c and -0.863c, respectively. Find the masses of the fragments. (Hint: Conserve both mass-energy and momentum.) m = 0.981c = _______kg m = -0.863c = ______kg
At time t=0 a positively charged particle of mass m=5.95 g and charge q=10.8 μC is injected into the region of the uniform magnetic
  At time t=0 a positively charged particle of mass m=5.95 g and charge q=10.8 μC is injected into the region of the uniform magnetic B=B k and electric E=−E k fields with the initial velocity v=v0 i. The magnitudes of the fields: B=0.43 T, E=722 V/m, and the initial speed v0=3.42 m/s are given. Find at what time t, the particle's speed would become equal to v(t)=4.14·v0: t =____ seconds.  
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT