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An unstable particle with a mass equal to 3.34x10^-27 kg is initially at rest. The particle...

An unstable particle with a mass equal to 3.34x10^-27 kg is initially at rest. The particle decays into two fragments that fly off with velocities of 0.981c and -0.863c, respectively. Find the masses of the fragments. (Hint: Conserve both mass-energy and momentum.)

m = 0.981c = _______kg

m = -0.863c = ______kg

Solutions

Expert Solution

According to the law of conservation of linear momentum wehave

               totalinitial momentum before decay = total final momentum afterdecay

Given that total intitial momentum of the system iszero.

Then 0 = m1v1 +m2v2

        (m1)(0.987c) + (m2)(-0.868c) = 0

            0.987m1 = 0.868m2

                    m1 = (0.868 / 0.987)m2

                         = 0.879m2 ....................(1)

Since we have m1 + m2 = 3.34 x10-27 kg

                    0.879m2 + m2 = 3.34 x 10-27 kg

                m2 ( 1 + 0.879) = 3.34 x 10-27 kg

From this we calculate the value of m2.

After getting the value of m2 substitute this valuein the eq(1) we get the value of m1.

genius_generous answered 9 months ago
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