In: Statistics and Probability
Faculty positions in a school district are classified as either teacher or administrator based on primary duties and responsibilities. The table below shows information on the number of national board-certified and not board-certified teachers and administrators.
Board-certified | Not board-certified | |
---|---|---|
Administrator | 10 | 6 |
Teacher | 5 | 18 |
Determine the probability, ?(board-certified or teacher), that a randomly chosen faculty member is either board-certified or a teacher. Please enter your answer as a decimal, precise to at least four decimal places.
?(board-certified or teacher) =
Lets find column total and row total for given contingency table :
Board-certified | Not board-certified | Total | |
Administrator | 10 | 6 | 16 |
Teacher | 5 | 18 | 23 |
Total | 15 | 24 | 39 |
Addition rule for two event probability :
If A and B are two dependent event , then P( A or B)= P(A) + P( B )- P( A and B )
?(board-certified or teacher) = P( Board-certified ) + P( Teacher) - P(board-certified and teacher)
Probability = number of favorable outcomes / total number of outcomes.
a) P( Board -certified) = Total number of board critified / Grand total .
Board-certified | Not board-certified | Total | |
Administrator | 10 | 6 | 16 |
Teacher | 5 | 18 | 23 |
Total | 15 | 24 | Grand total =39 |
P( Board -certified) = Total number of board critified / Grand total . = 15 / 39
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b ) P(Teacher ) Total number of teacher / Grand total
Board-certified | Not board-certified | Total | |
Administrator | 10 | 6 | 16 |
Teacher | 5 | 18 | 23 |
Total | 15 | 24 | Grand total =39 |
P(Teacher ) Total number of teacher / Grand total = 23 / 39
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c ) ?(board-certified and teacher) = number of board -certified and teacher / grand total.
Board-certified | Not board-certified | Total | |
Administrator | 10 | 6 | 16 |
Teacher | 5 | 18 | 23 |
Total | 15 | 24 | Grand total =39 |
?(board-certified and teacher) = number of board -certified and teacher / grand total.
= 5 / 39
Final answer :
?(board-certified or teacher) = P( Board-certified ) + P( Teacher) - P(board-certified and teacher)
=15/39 + 23/39 - 5 /39
= 33/39 ==>>0.8462