Question

In: Statistics and Probability

Faculty positions in a school district are classified as either teacher or administrator based on primary...

Faculty positions in a school district are classified as either teacher or administrator based on primary duties and responsibilities. The table below shows information on the number of national board-certified and not board-certified teachers and administrators.

Board-certified Not board-certified
Administrator 10 6
Teacher 5 18

Determine the probability, ?(board-certified or teacher), that a randomly chosen faculty member is either board-certified or a teacher. Please enter your answer as a decimal, precise to at least four decimal places.

?(board-certified or teacher) =

Solutions

Expert Solution

Lets find column total and row total for given contingency table :

Board-certified Not board-certified Total
Administrator 10 6 16
Teacher 5 18 23
Total 15 24 39

Addition rule for two event probability :

If A and B are two dependent event , then P( A or B)= P(A) + P( B )- P( A and B )

?(board-certified or teacher) = P( Board-certified ) + P( Teacher) - P(board-certified and teacher)

Probability = number of favorable outcomes / total number of outcomes.

a) P( Board -certified) = Total number of board critified / Grand total .

   

Board-certified Not board-certified Total
Administrator 10 6 16
Teacher 5 18 23
Total 15 24 Grand total =39

P( Board -certified) = Total number of board critified / Grand total . = 15 / 39

--------------------------------------------------

b ) P(Teacher ) Total number of teacher / Grand total

Board-certified Not board-certified Total
Administrator 10 6 16
Teacher 5 18 23
Total 15 24 Grand total =39

P(Teacher ) Total number of teacher / Grand total = 23 / 39

-----------------------------------------------------

c ) ?(board-certified and teacher) = number of board -certified and teacher / grand total.

Board-certified Not board-certified Total
Administrator 10 6 16
Teacher 5 18 23
Total 15 24 Grand total =39

?(board-certified and teacher) = number of board -certified and teacher / grand total.

                                            = 5 / 39

Final answer :

?(board-certified or teacher) = P( Board-certified ) + P( Teacher) - P(board-certified and teacher)

                                           =15/39 + 23/39 - 5 /39

                                          = 33/39 ==>>0.8462


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