In: Physics
A particle travels at 0.14c. By what percentage will a calculation of its momentum be wrong if you use the classical formula?
Express your answer using two significant figures.
p−prelprel = ? %
B- Repeat for
0.58c.
Express your answer using two significant figures
p−prelprel = ? %
(A) velocity of a particle, v = 0.14 c
we know that, classical momentum is given as -
p0 = m v { eq.1 }
Relativistic momentum is given as -
prel = m v { eq.2 }
The percent difference will be given as,
( m v - m v) / m v = ( - 1) /
1 - (1 / ) { eq.3 }
where, = 1 / 1 - (v / c)2
inserting the value of 'v'
= 1 / 1 - (0.14)2
= 1 / 1 - (0.0196)
= 1 / (0.99015)
= 1.0099
now, we have 1 - (1 / 1.0099) = 0.009802 or 0.98 %
(B) For v = 0.58c
using eq.3, 1 - (1 / )
where, = 1 / 1 - (v / c)2
inserting the value of 'v'
= 1 / 1 - (0.58)2
= 1 / 1 - (0.3364)
= 1 / (0.81461)
= 1.2275
now, we have 1 - (1 / 1.2275) = 0.185 or 18.5 %