In: Physics
A particle travels at 0.14c. By what percentage will a calculation of its momentum be wrong if you use the classical formula?
Express your answer using two significant figures.
p−prelprel = ? %
B- Repeat for
0.58c.
Express your answer using two significant figures
p−prelprel = ? %
(A) velocity of a particle, v = 0.14 c
we know that, classical momentum is given as -
p0 = m v { eq.1 }
Relativistic momentum is given as -
prel = 
 m
v                                                                                                
{ eq.2 }
The percent difference will be given as,
(
 m v - m v)
/ 
 m v =
(
 - 1) /

1 - (1 / 
)                                                                                                          
{ eq.3 }
where, 
 = 1 /
1 - (v /
c)2
inserting the value of 'v'
 = 1 /
1 -
(0.14)2
 = 1 /
1 -
(0.0196)
 = 1 /
(0.99015)
 =
1.0099
now, we have 1 - (1 / 1.0099) = 0.009802 or 0.98 %
(B) For v = 0.58c
using eq.3,    1 - (1 / 
)    
where, 
 = 1 /
1 - (v /
c)2
inserting the value of 'v'
 = 1 /
1 -
(0.58)2
 = 1 /
1 -
(0.3364)
 = 1 /
(0.81461)
 =
1.2275
now, we have 1 - (1 / 1.2275) = 0.185 or 18.5 %