In: Statistics and Probability
A survey of 1060 randomly selected US teens ages 13 to 17 found that 605 of them say they have made a new friend online.
Find and interpret a 90% confidence interval for the proportion of US teens who have made a new friend online.
Fill in the blanks
a) The scenario above represents (write either test or CI):
b) The population parameter (write either single proportion or single mean):
c) The sample size:
d) The sample statistic (round decimal answer to 2 decimal places):
e) Look at the table below and state the value of z* for 90% confidence level:
A survey of N = 1060 randomly selected US teens ages 13 to 17 found that X = 605 of them say they have made a new friend online.
The confidence interval is calculated as:
Where the sample proportion is calculated as:
and the Zc at 90% confidence level is calculated using the excel formula for normal distribution which is =NORM.S.INV(0.95), thus the Zc is computed as 1.645.
Now the confidence interval is calculated as:
Interpretation:
Thus at 90 % confidence, we can say that the confidence interval for the true population proportion is between 0.546 and 0.596.
Fill in the blanks
a) The scenario above represents (write either test or CI):
This represents the confidence interval CI
b) The population parameter (write either single proportion or single mean):
The population parameter is the value with help of which we can estimate the population, here the population parameter is sample proportion.
c) The sample size:
The sample is the no of value on which the experiments are conducted and taken from a large population, here the sample size is N = 1060
d) The sample statistic (round decimal answer to 2 decimal places):
The sample statistic is the sample proportion which is calculated as:
Thus 0.57
e) Look at the table below and state the value of z* for a 90% confidence level:
The Z value is at 90% confidence level is calculated using the excel formula for normal distribution which is =NORM.S.INV(0.95), thus the Zc is computed as 1.645.