Question

Liquid chlorotribromethane has a density of 2.71 g/mL. A barometer is constructed using chlorotribromethane instead of mercury. If the atmospheric pressure is 0.953 atm, what is the height of the chlorotribromethane column in the barometer in cm?
the density of liquid mercury is 13.6g/mL

A prevailing of one standard atmosphere will support a column of mercury 760 mm in height. Liquid 1,2,3-trichlorobutane has a density of 1.32g/mL. The height of a column of 1,2,3-trichlorobutane that one standard atmosphere can support is ____mm.
The density of liquid mercury is 13.6g/mL.

Answer 1

Pressure = d(density of fluid) x g (acceleration due to gravity) x h (height of the fluid)

One standard atmosphere corresponds to a height of 76 cm mercury in a barometer.

Therefore, height of mercury corresponding to 0.983 atm will be = 0.983x76

= 74.71 cm

Now, let the corresponding height for the same pressure of 0.983 atm for chlorotribromethane be h_{chlorotribromethane}

Then, we have

d_mercury x g x h_mercury=d_{chlorotribromethane} x g x h_{chlorotribromethane}

13.6 x g x 74.71 =2.71 x g x h_{chlorotribromethane}

h_{chlorotribromethane} = (13.6 x 74.71)/2.71

= 374.93 cm

This is similar to the above part

One standard atmosphere corresponds to a height of 760 mm mercury in a barometer.

Now, let the corresponding height for the same standard pressure of 1 atm for 1,2,3-trichlorobutane be h_{1,2,3-trichlorobutane}

Then, we have

d_mercury x g x h_mercury= d_{1,2,3-trichlorobutane} x g x  h_{1,2,3-trichlorobutane​}

13.6 x g x 760 =1.32 x g x h_{1,2,3-trichlorobutane​}

h_{1,2,3-trichlorobutane}= (13.6 x 760)/1.32

= 7830.3 mm