Question

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A container has 9.0 ml of liquid X with a density of 1200 kg/m3. How much...

A container has 9.0 ml of liquid X with a density of 1200 kg/m³. How much liquid Y with a density of 1400 kg/m³ should be added to the flask so that the density of the liquid mixture is 1280 kg/m³?

Solutions

Expert Solution

Ans

The volume of liquid Y = 6 ml should be added to the flask.

Explanation

The density of liquid X is _x = 1200 Kg/m³

The volume of liquid X is V_x = 9.0 ml

As 1 ml = 10^-6 m³

Thus V_x = 9.0 10^-6 m³

Mass of liquid X is M_x = _x V_x = 1200 9.0 10^-6

M_x = 1.080 10^-2 Kg

The density of liquid Y is _y = 1400 Kg/m³

Let V_y volume of liquid Y should be added to the flask

Mass of liquid Y is M_y = _y V_y = 1400 V_y

Total Mass in flask M = M_x + M_y

M = 1.080 10^-2 + 1400 V_y

Total volume in flask V = V_x + V_y

V = 9.0 10^-6 + V_y

Density of liquid mixture is = 1280 Kg/m³

1280 (9.0 10^-6 + V_y ) = 1.080 10^-2 + 1400 V_y

1.152 10^-2 + 1280 V_y = 1.080 10^-2 + 1400 V_y

1.152 10^-2 - 1.080 10^-2 = 1400 V_y - 1280 V_y

0.072 10^-2 = 120 V_y

V_y = 6 10^-6 m³

V_y = 6 ml

Cheers

genius_generous answered 1 year ago

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