Question

Find the probability and interpret the results. If convenientt, use technology to find the probability. The population mean annual salary for environmental compliance specialists is about

$62,500. A random sample of 33 specialists is drawn from this population. What is the probability that the mean salary of the sample is less than $59,500? Assume

σ = $6,000. The probability that the mean salary of the sample is less than $59,500 is

Answer 1

Solution :

Given that ,

mean = = 62500

standard deviation = = 6000

n = 33

= 62500 and

= / n = 6000 / 33 = 1044.466

P( < 59500) = P(( - ) / < (59500 - 62500) / 1044.466)

= P(z < -2.87)

Using standard normal table,

P( < 59500) = 0.0021

Probability = 0.0021