Question

In: Statistics and Probability

Oysters are categorized for retail as small, medium, or large based on their volume. The grading...

Oysters are categorized for retail as small, medium, or large based on their volume. The grading process is slow and expensive when done by hand. A computer reconstruction of oyster volume based on image analysis would be desirable to speed the process. Engineers designed two programs estimating oyster volume, one based on two‑dimensional ( 2D ) image processing and the other based on three‑dimensional ( 3D ) image processing. We want to know if either approach is a good predictor of actual oyster volume. The results of both programs are given in the table for a sample of 30 oysters. Actual volumes are expressed in cubic centimeters (cm3) , 2D reconstructions in thousands of pixels and 3D reconstruction in millions of volume pixels.

To access the complete data set, click the link for your preferred software format: Excel Minitab JMP SPSS TI R Mac-TXT PC-TXT CSV CrunchIt! Consider the program that estimates oyster volume using 3D digital income processing.

(a) Use the software of your choice to create a scatterplot of 3D volume reconstruction and actual volume, using 3D reconstruction for the explanatory variable. Find the equation of the least‑squares regression line. ?̂ = ?

(b) Select the statement that verifies the conditions for inference.

-The relationship is clearly non‑linear, the scatterplot shows some unusual patterns that would indicate Normally distributed residuals or residuals with a constant standard deviation, and the observations are not independent.

-The relationship is clearly linear, the scatterplot shows some unusual patterns that would result in non‑Normally distributed residuals or residuals without a constant standard deviation, and the observations are independent.

-The relationship is clearly linear, the scatterplot shows no unusual pattern that would indicate not Normally distributed residuals or residuals without a constant standard deviation, and the observations are independent.

-The relationship is non‑linear, the scatterplot shows no unusual pattern that would indicate not Normally distributed residuals or residuals without a constant standard deviation, and the observations are independent.

(c) What are the null and alternative hypotheses to test whether the linear relationship is statistically significant?

-?0:?=0 versus ??:?≠0

-?0:?=0 versus ??:?<0

-?0:?=0 versus ??:?>0

-None of the other choices are correct.

(d) What is the test statistic ? ? (Enter your answer rounded to two decimal places.) ?=

(e) What are the degrees of freedom? (Enter your answer rounded to the nearest whole number.) df=

(f) What is the ? ‑value? You may find Table C helpful.

-?<0.05

-0.05≤?≤0.1

-0.1<?<0.5

-?>0.5

(g) Which is the most appropriate conclusion of your test?

-We have strong evidence of a positive linear relationship between 3D reconstruction and actual oyster volumes.

-None of the other choices are correct.

-We have weak evidence of a positive linear relationship between 3D reconstruction and actual oyster volumes.

-We have no evidence of a positive linear relationship between 3D reconstruction and actual oyster volumes.

The 95% confidence interval for the population slope ? is lower bound to upper bound cm3 per million volume pixels. (Enter your answers rounded to three decimal places.) lower bound:

upper bound:

Data:

Actual 3D 2D
13.04 5.136699 47.907
11.71 4.795151 41.458
17.42 6.453115 60.891
7.23 2.895239 29.949
10.03 3.672746 41.616
15.59 5.72888 48.07
9.94 3.987582 34.717
7.53 2.678423 27.23
12.73 5.481545 52.712
12.66 5.016762 41.5
10.53 3.942783 31.216
10.84 4.052638 41.852
13.12 5.334558 44.608
8.48 3.527926 35.343
14.24 5.679636 47.481
11.11 4.013992 40.976
15.35 5.565995 65.361
15.44 6.303198 50.91
5.67 1.928109 22.895
8.26 3.450164 34.804
10.95 4.707532 37.156
7.97 3.019077 29.07
7.34 2.76816 24.59
13.21 4.945743 48.082
7.83 3.138463 32.118
11.38 4.410797 45.112
11.22 4.558251 37.02
9.25 3.449867 39.333
13.75 5.609681 51.351
14.37 5.292105 53.281

Solutions

Expert Solution

a)

he above scatter plot show's that the actual value is positive correlated with 3D variable and it show any increasing pattern means that they are linearly related each other.

The correlation between between 3D variable and actual value is 0.9765

The equation of the least‑squares regression line.

?̂= ?(b)

?̂=0.41945+2.475*x

Regression Analysis
0.954 n   30
r   0.977 k   1
Std. Error   0.649 Dep. Var. Actual
ANOVA table
Source SS   df   MS F p-value
Regression 242.8360 1   242.8360 576.93 3.17E-20
Residual 11.7855 28   0.4209
Total 254.6214 29  
Regression output confidence interval
variables coefficients std. error    t (df=28) p-value 95% lower 95% upper
Intercept 0.4196
3D 2.4752 0.1031 24.019 3.17E-20 2.2641 2.6863

c) The null and alternative hypotheses to test whether the linear relationship is statistically significant or not

?0:?=0 versus ??:?≠0

The value of F-stat =576.85 and the value of F-tab= 3.17118E-20

The F-stat value is greater than F-tab value means that Reject Ho

i.e. Conclusion: The linear relationship is statistically significant between 3D variable and Response actual value at 5% of level of significance.(?≠0)

The test statistic ? =0.897872771

The p-value is 3.17118E-20

It is appropriate conclusion given below for p-value with 5% l.o.s.

The above p-value for 3D variable is less than alpha value then Reject Ho (null hypothesis)

It is conclude that the variable is significance at 5% of level of significance.

The 95% confidence interval for the population slope ? is lower bound to upper bound cm3 per million

lower bound =2.264

upper bound =2.6863


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