In: Statistics and Probability
The success of an airline depends heavily on its ability to provide a pleasant customer experience. One dimension of customer service on which airlines compete is on-time arrival. The tables below contains a sample of data from delayed flights showing the number of minutes each delayed flight was late for two different airlines, Company A and Company B.
34 | 59 | 43 | 30 | 3 |
32 | 42 | 85 | 30 | 48 |
110 | 50 | 10 | 26 | 70 |
52 | 83 | 78 | 27 | 70 |
27 | 90 | 38 | 52 | 76 |
44 | 64 | 41 | 32 | 65 |
104 | 45 | 27 | 37 | 84 |
76 | 45 | 34 | 51 | 63 |
43 | 34 | 32 | 63 | 66 |
(a)
Formulate the hypotheses that can be used to test for a difference between the population mean minutes late for delayed flights by these two airlines. (Let μ1 = population mean minutes late for delayed Company A flights and μ2 = population mean minutes late for delayed Company B flights.)
H0: μ1 − μ2 ≤ 0
Ha: μ1 − μ2 > 0
H0: μ1 − μ2 < 0
Ha: μ1 − μ2 = 0
H0: μ1 − μ2 ≥ 0
Ha: μ1 − μ2 < 0
H0: μ1 − μ2 = 0
Ha: μ1 − μ2 ≠ 0
H0: μ1 − μ2 ≠ 0
Ha: μ1 − μ2 = 0
(b)
What is the sample mean number of minutes late for delayed flights for each of these two airlines?
Company A minCompany B min
(c)
Calculate the test statistic. (Round your answer to three decimal places.)
What is the p-value? (Round your answer to four decimal places.)
p-value =
Using a 0.05 level of significance, what is your conclusion?
Reject H0. There is statistical evidence that one airline does better than the other in terms of their population mean delay time.Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time. Do not Reject H0. There is statistical evidence that one airline does better than the other in terms of their population mean delay time.Reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.
A | B | (A-A_bar)^2 | (B-B_bar)^2 | |
34 | 44 | 275.56 | 72.25 | |
59 | 64 | 70.56 | 132.25 | |
43 | 41 | 57.76 | 132.25 | |
30 | 32 | 424.36 | 420.25 | |
3 | 65 | 2265.76 | 156.25 | |
32 | 104 | 345.96 | 2652.25 | |
42 | 45 | 73.96 | 56.25 | |
85 | 27 | 1183.36 | 650.25 | |
30 | 37 | 424.36 | 240.25 | |
48 | 84 | 6.76 | 992.25 | |
110 | 76 | 3528.36 | 552.25 | |
50 | 45 | 0.36 | 56.25 | |
10 | 34 | 1648.36 | 342.25 | |
26 | 51 | 605.16 | 2.25 | |
70 | 63 | 376.36 | 110.25 | |
52 | 43 | 1.96 | 90.25 | |
83 | 34 | 1049.76 | 342.25 | |
78 | 32 | 750.76 | 420.25 | |
27 | 63 | 556.96 | 110.25 | |
70 | 66 | 376.36 | 182.25 | |
27 | 556.96 | |||
90 | 1552.36 | |||
38 | 158.76 | |||
52 | 1.96 | |||
76 | 645.16 | |||
Total | 1265 | 1050 | 16938 | 7713 |
A_bar | B_bar | |||
mean | 50.6 | 52.5 | ||
n | 25 | 20 | ||
S1 | S2 | |||
SD | 26.56596 | 20.14814 | ||
Sample means:
A_bar | B_bar | |
mean | 50.6 min | 52.5 min |
Hypothesis:
H0: μ1 − μ2 = 0
V/s
Ha: μ1 − μ2 ≠ 0
under Ho,
(assuming equal variances)
Where,Pooled Standard deviation,
Decision : If p-value < alpha then we reject Ho.
Calculation :
DF = 43
WE find p-value using Excel
=T.DIST.2T(0.265,43)
=0.7923
At 0.05 level level of significance
p-value = 0.7923 > alpha = 0.05 then we fail to reject Ho.
Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.