A force of 720 Newton stretches a spring 4 meters. A mass of 45 Kilograms is...

A force of 720 Newton stretches a spring 4 meters. A mass of 45 Kilograms is attached to the spring and is initially released from the equilibrium position with an upward velocity of 6 meters per second. Find an equation of the motion.

Expert Solution

If you have any doubts please ask me in comments ...

Here i used hooke law and newton law and spring law and diffrentiation law

Colby Messinger answered 2 years ago

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