Question
In: Economics
Given that z is a standard normal random variable, find z for each situation. (Draw the...
- Given that z is a standard normal random variable, find z for each situation. (Draw the graph in a paper with numbers going from -3 to +3. No need to draw it here for credit. But do it for your own learning.)
- The area to the left of z is 0.025
- The area to the right of z is 0.975.
- The area to the right of z is 0.025.
- The area to the left of z is .6700.
- Suppose X it a normally distributed random variable with mean
of 328 and standard deviation of 92.
- What is the z-score of X=500?
- What is the z-score of X=250?
- What is the first quartile (the 25% percentile) of X?
Solutions
Rahul Sunny answered 1 year agoRelated Solutions
Given that z is a standard normal random variable, find z for each situation.
Given that z is a standard normal random variable, find z for each situation. (Round your answers to two decimal places.)
(a) The area to the left of z is 0.2119.
(b) The area between −z and z is 0.9398.
(c) The area between −z and z is 0.2052.
(d) The area to the left of z is 0.9949.
(e) The area to the right of z is 0.5793.
Given that Z is a standard normal random variable, find z for each situation using the...
Given that Z is a standard normal random variable, find z for
each situation using the Norm.S.Inv function in excel.
a. The area to the right of z is .01
b. The area between -z and z is .9030
c. The area between -z and z is .9948
e. The area to the right of z is .025
f. The area to the right of z is .3300
Given that z is a standard normal random variable, find z for each situation. (Round your...
Given that z is a standard normal random variable, find
z for each situation. (Round your answers to two decimal
places.)
(a)
The area to the left of z is 0.1841.
(b)
The area between −z and z is 0.9534.
(c)
The area between −z and z is 0.2206.
(d)
The area to the left of z is 0.9948.
(e)
The area to the right of z is 0.6915.
Given that z is a standard normal random variable, find z for each situation. (Round your...
Given that z is a standard normal random variable, find
z for each situation. (Round your answers to two decimal
places.)
A.The area to the right of z is 0.08.
B.The area to the right of z is 0.025.
C.The area to the right of z is 0.05.
D.The area to the right of z is 0.10.
Given that z is a standard normal random variable, find z for each situation. (Round your answers to two decimal places.)
Given that z is a standard normal random variable, find z for each situation. (Round your answers to two decimal places.)
(a)
The area to the left of z is 0.1841.
(b)
The area between −z and z is 0.9398.
(c)
The area between −z and z is 0.2052.
(d)
The area to the left of z is 0.9948.
(e)
The area to the right of z is 0.6915.
For a random variable Z, that follows a standard normal distribution, find the values of z...
For a random variable Z, that follows a standard normal
distribution, find the values of z required for these probability
values:
P(Z<z)=.5 =
P(Z<z)=.1587 =
P(Z<z)=.8413 =
Please show how to solve without using excel.
Please show all steps.
Thank you!
Let z be a random variable with a standard normal distribution. Find “a” such that P(|Z|...
Let z be a random variable with a standard normal
distribution.
Find “a” such that P(|Z| <A)= 0.95
This is what I have:
P(-A<Z<A) = 0.95
-A = -1.96
How do I use the symmetric property of normal distribution to make
A = 1.96?
My answer at the moment is P(|z|< (-1.96) = 0.95
Find a value of the standard normal random variable z , call it z 0z0, a....
Find a value of the standard normal random variable z , call it
z 0z0,
a.
P(zless than or equals≤z 0z0)equals=0.0703
e.
P(minus−z 0z0less than or equals≤zless than or
equals≤0)equals=0.2960
b.
P(minus−z 0z0less than or equals≤zless than or equals≤z
0z0)equals=0.95
f.
P(minus−22less than<zless than<z 0z0)equals=0.9516
c.
P(minus−z 0z0less than or equals≤zless than or equals≤z
0z0)equals=0.99
g.
P(zless than<z 0z0)equals=0.5
d.
P(minus−z 0z0less than or equals≤zless than or equals≤z
0z0)equals=0.8586
h.
P(zless than or equals≤z 0z0)equals=0.0065
Find the value of the standard normal random variable z , called z 0 such that:...
Find the value of the standard normal random variable z , called
z 0 such that:
a) ?(?≤?0)=0.8998
?0=
(b) ?(−?0≤?≤?0)=0.676
?0=
(c) ?(−?0≤?≤?0)=0.198
?0=
(d) ?(?≥?0)=0.1895
?0=
(e) ?(−?0≤?≤0)=0.4425
?0=
(f) ?(−1.11≤?≤?0)=0.8515
?0=
Find a value of the standard normal random variable z , call it z 0, such...
Find a value of the standard normal random variable z , call it
z 0, such that the following probabilities are satisfied.
a. P(z less than or equals z 0) equals 0.3027
b. P(minus z 0less than or equals z less than z 0) equals
0.1518
c. P(z less than or equals z 0) equals0.7659
d. P(z 0 less than or equals z less than or equals 0) equals
0.2706
e. P( minus z 0 less than or equals z...
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