Question

In: Chemistry

In BBr4−, boron has _____ hybrid orbital(s). In BrCl3, bromine has ______ hybrid orbital(s). In CS2,...

In BBr4, boron has _____ hybrid orbital(s).

In BrCl3, bromine has ______ hybrid orbital(s).

In CS2, carbon has _______ hybrid orbital(s).

Solutions

Expert Solution

Number of hybrid orbitals,H = (V+S-C+A)/2

Where

V = number of valence electrons on the central atom

S = Number of monovalent atoms

C = charge of cation including sign

A = charge of anoin including charge

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BBr4-

The central atom is B

Br is monovalent atom

H = (3+4-0+(-1)) / 2

   = 4

So the hybridization of B is (4) sp3

BrCl3 :

The central atom is Br

Cl is monovalent atom

H = (7+3-0+0) / 2

   = 5

So the hybridization of Br is (5) sp3 d

CS2 :

The central atom is C

S is divalent atom

H = (4+0-0+0) / 2

   = 2

So the hybridization of C is (2) sp


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