In: Chemistry
In BBr4−, boron has _____ hybrid orbital(s).
In BrCl3, bromine has ______ hybrid orbital(s).
In CS2, carbon has _______ hybrid orbital(s).
Number of hybrid orbitals,H = (V+S-C+A)/2
Where
V = number of valence electrons on the central atom
S = Number of monovalent atoms
C = charge of cation including sign
A = charge of anoin including charge
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BBr4-
The central atom is B
Br is monovalent atom
H = (3+4-0+(-1)) / 2
= 4
So the hybridization of B is (4) sp3
BrCl3 :
The central atom is Br
Cl is monovalent atom
H = (7+3-0+0) / 2
= 5
So the hybridization of Br is (5) sp3 d
CS2 :
The central atom is C
S is divalent atom
H = (4+0-0+0) / 2
= 2
So the hybridization of C is (2) sp