Question
In: Statistics and Probability
In a research study comparing two different types of aortas (a healthy aorta and a repaired...
In a research study comparing two different types of aortas (a healthy aorta and a repaired aorta), researchers recorded the number of individuals with each type of aortas who had reduced blood flow. For the individuals with the healthy aortas, 28 had reduced blood flow, and 83 did not. In the group with the repaired aortas, 55 patients had reduced blood flow, and 180 did not. Do the confidence intervals overlap? Explain briefly the meaning of any overlap or lack of overlap. How would you interpret the results of this study?
a) Calculate a 90% confidence interval for percentage of individuals in each population who have reduced blood flow (keeping the two groups separate). State each confidence interval in a sentence.
b) Do the confidence intervals overlap? How can you interpret the results of this study, based on whether there is or is not any overlap?
Solutions
orchestra answered 2 years agoRelated Solutions
In a research study comparing two different types of aortas (a healthy aorta and a repaired...
In a research study comparing two different types of aortas (a
healthy aorta and a repaired aorta), researchers recorded the
number of individuals with each type of aortas who had reduced
blood flow. For the individuals with the healthy aortas, 28 had
reduced blood flow, and 83 did not. In the group with the repaired
aortas, 55 patients had reduced blood flow, and 180 did not.
a) Calculate a 90% confidence interval for percentage of
individuals in each population who...
A research study is comparing the aorta diameters of patients who have aortic disorders to the...
A research study is comparing the aorta diameters of patients
who have aortic disorders to the aortas of those who do not have
any disorders. The aorta diameters of 15 cases (those with aortic
disorders) were measured. The results are given below, measured in
millimeters (mm):
7.22, 9.24, 12.01, 7.18, 9.17, 8.26, 14.03, 10.55, 11.09, 10.17,
8.56, 8.29, 7.87, 11.24, 13.14
a) Because the sample size is small, to compute a confidence
interval for the mean, we must assume that...
A research study is comparing the aorta diameters of patients who have aortic disorders to the...
A research study is comparing the aorta diameters of patients
who have aortic disorders to the aortas of those who do not have
any disorders. The aorta diameters of 15 cases (those with aortic
disorders) were measured. The results are given below, measured in
millimeters (mm):
7.22, 9.24, 12.01, 7.18, 9.17, 8.26, 14.03, 10.55, 11.09, 10.17,
8.56, 8.29, 7.87, 11.24, 13.14
a) Because the sample size is small, to compute a confidence
interval for the mean, we must assume that...
A consumer electronics company is comparing the brightness of two different types of picture tubes for...
A consumer electronics company is comparing the brightness of
two different types of picture tubes for use in its television
sets. Tube type A has mean brightness of 100 and standard deviation
of 16, and tube type B has unknown mean brightness, but the
standard deviation is assumed to be identical to that for type A. A
random sample of n=25 tubes of each type is selected, and
XB bar - XA bar is computed. If μB
equals or exceeds...
Research Paradigms: Different kinds of research require different types of paradigms. Identify three types of research...
Research Paradigms: Different kinds of research
require different types of paradigms. Identify three types of
research and the appropriate paradigm for each.
Suppose we are comparing average scores on a test for two groups that used different study...
Suppose we are comparing average scores on a test for two groups
that used different study techniques. The null hypothesis is that
μ1 - μ2 = 0 A. If μ1 = 84 and μ2 = 80, which of the following are
true (select all that apply)?
If we fail to reject H0, we are making the correct decision
If we fail to reject H0, we are committing a Type I error
If we fail to reject H0, we are committing...
(Chapter 15) A psychologist conducts a two-factor study comparing the effectiveness of two different therapy techniques...
(Chapter 15) A psychologist conducts a two-factor study
comparing the effectiveness of two different therapy techniques
(factor A) for treating mild and severe phobias (factor B). The
dependent variable is a measure of fear for each participant. If
the study uses n= 9 participants in each of the five conditions,
then identify the df values for each of the three
F-Ratios. Be sure to show all formulas with symbols (and
plug in numbers), steps, processes and calculations for all steps
and...
You are conducting a study comparing two different treatments for post-surgical recovery. Group A, consisting of...
You are conducting a study comparing two different treatments
for post-surgical recovery. Group A, consisting of 10 patients from
your clinic, will be given the current standard treatment. Group B,
consisting of 10 different patients from your clinic, will be given
a new experimental treatment. Both groups of patients have
undergone the same surgery in the last month.
Table 1. Number of post-surgical recovery days reported by
group.
Group A
Group B
3 days
5 days
8 days
5 days...
An analysis of variance is used to evaluate the mean differences for a research study comparing...
An analysis of variance is used to evaluate the mean differences
for a research study comparing four treatments with a separate
sample of n = 8 in each treatment. If the data produce an F-ratio
of F = 4.60, which of the following is the correct statistical
decision? Please show work. a. Reject the null hypothesis with α =
.05 but not with α = .01 b. Reject the null hypothesis with either
α = .05 or α = .01...
DATA SET 2 The following data were obtained from a research study comparing two treatment conditions....
DATA SET 2
The following data were obtained from a research study comparing
two treatment conditions. Analyze this data to determine whether
you will reject or fail to reject the null hypothesis based upon
your results. Two-tailed test. Alpha = .05 (Please show work)
Treatment 1
Treatment 2
10
7
8
4
7
9
9
3
13
7
7
6
6
10
12
2
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