Question

In: Physics

Sketch a graph of ax(t) for the car in Problem 43.

Sketch a graph of ax(t) for the car in Problem 43.

Solutions

Expert Solution

The acceleration is defined as the rate of change of velocity. The slope of vx(t) graph gives acceleration of the object. As the velocity of the object increase linearly, then the object has constant acceleration and the acceleration is zero, when the velocity is constant. The slope of the graph of vx(t) gives the acceleration of the car.

The graph of vx(t) shown in problem 37, corresponds to the car is traveling with uniform velocity from 0 s to 6 s. As the acceleration is the rate of change of velocity, the corresponding acceleration of the car at the time interval is equal to zero. This means the graph will be a straight line coinciding with the time axis in the graph of ax(t).

In the time interval 6 s to 11 s, the velocity of the car is increasing uniformly, which gives the acceleration of the car is constant. This can also be inferred from the fact that the slope of the graph is constant in the given interval. The acceleration of the car is

a = AB/AC

   = 10m/s/5s

   = 2 m/s2

This means the graph will be parallel to the time axis intercepting the acceleration axis at 2 m/s2.

From 11 s to 20 s, the car is traveling at the constant velocity of 14 m/s. This means the acceleration of the car is equal to zero. This means the graph will be a straight line coinciding with the time axis in the graph of ax(t).

The following figure shows the corresponding graph of ax(t).

The acceleration is defined as the rate of change of velocity. The slope of vx(t) graph gives acceleration of the object.

Junaid answered 1 year ago
Next > < Previous

Related Solutions

a) Sketch the graph of the solution to the initial value problem. dy/dx = sin x...
a) Sketch the graph of the solution to the initial value problem. dy/dx = sin x , y(0) = 1 over the interval 0 ≤ x ≤ 4π b) By finding a suitable antiderivative, evaluate y(2)
2. In each of the following problem sketch the graph of f(y) versus y, determine the...
2. In each of the following problem sketch the graph of f(y) versus y, determine the equilibrium solutions, and classify each one as asymptotically stable, asymptotically unstable, or semi-stable. Draw the phase line, and sketch several graphs of solutions in the ty-plane. Here y0 = y(0). (a) dy/dt = e ^y − 1, −∞ < y0 < ∞ (b) dy/dt = (e^-y) − 1, −∞ < y0 < ∞ (c) dy/dt = (y^2)* (1 − y)^ 2 , −∞ <...
Sketch the graph of f by hand and use your sketch to find the absolute and...
Sketch the graph of f by hand and use your sketch to find the absolute and local maximum and minimum values of f. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) f(t) = 2 cos(t),    −3π/2 ≤ t ≤ 3π/2 absolute maximum value     absolute minimum value local maximum value(s) local minimum value(s)
Sketch the graph of f by hand and use your sketch to find the absolute and...
Sketch the graph of f by hand and use your sketch to find the absolute and local maximum and minimum values of f. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) f(x) = x2     if −1 ≤ x ≤ 0 2 − 3x     if 0 < x ≤ 1 absolute maximum value     absolute minimum value local maximum value(s) local minimum value(s)
Sketch the graph of f by hand and use your sketch to find the absolute and...
Sketch the graph of f by hand and use your sketch to find the absolute and local maximum and minimum values of f. (If an answer does not exist, enter DNE.) Absolute maximum, absolute minimum, local maximum, local minimum. f(x) = ln 3x, 0 < x ≤ 7 Find the absolute maximum and absolute minimum values of f on the given intervals(absolute maximum, absolute minimum). f(x) = 6x^3 − 9x^2 − 216x + 3, [−4, 5] f(x) = x/x^2 −...
A small object moves along the xx-axis with acceleration ax(t)ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At tt = 0the...
A small object moves along the xx-axis with acceleration ax(t)ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At tt = 0the object is at xx = -14.0 mm and has velocity v0xv0x = 4.10 m/sm/s. Part A What is the xx-coordinate of the object when tt = 10.0 ss?
A small object moves along the xx-axis with acceleration ax(t)ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At tt = 0...
A small object moves along the xx-axis with acceleration ax(t)ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At tt = 0 the object is at xx = -14.0 mm and has velocity v0xv0x = 8.70 m/sm/s. What is the xx-coordinate of the object when tt = 10.0 ss? Express your answer with the appropriate units.
Type or paste question here ax+by+c=0.ax+by+c=0. Let (s′,t′)(s′,t′) be the reflection of the point (s,t)(s,t) in...
Type or paste question here ax+by+c=0.ax+by+c=0. Let (s′,t′)(s′,t′) be the reflection of the point (s,t)(s,t) in ℓℓ. Find a formula that computes the coordinates of (s′,t′)(s′,t′) if one knows the numbers s,t,a,bs,t,a,b and cc. Your formula should depend on the variables s,t,a,bs,t,a,b and cc. It should work for arbitrary values of s,t,a,bs,t,a,b and cc as long as (a,b)≠(0,0)(a,b)≠(0,0). Its output should be a point.
Sketch the graph of the curve ? = 1 + sin ? for 0 ≤ ?...
Sketch the graph of the curve ? = 1 + sin ? for 0 ≤ ? ≤ 2? ? b) Find the slope of the tangent line to this curve at ? = 4 . c) Find the polar coordinates of the points on this curve where the tangent line is horizontal.
Sketch the graph of y = x3 − 3x + 3.
Sketch the graph of y = x3 − 3x + 3.
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT