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Sketch a graph of ax(t) for the car in Problem 43.

Sketch a graph of ax(t) for the car in Problem 43.

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Expert Solution

The acceleration is defined as the rate of change of velocity. The slope of vx(t) graph gives acceleration of the object. As the velocity of the object increase linearly, then the object has constant acceleration and the acceleration is zero, when the velocity is constant. The slope of the graph of vx(t) gives the acceleration of the car.

The graph of vx(t) shown in problem 37, corresponds to the car is traveling with uniform velocity from 0 s to 6 s. As the acceleration is the rate of change of velocity, the corresponding acceleration of the car at the time interval is equal to zero. This means the graph will be a straight line coinciding with the time axis in the graph of ax(t).

In the time interval 6 s to 11 s, the velocity of the car is increasing uniformly, which gives the acceleration of the car is constant. This can also be inferred from the fact that the slope of the graph is constant in the given interval. The acceleration of the car is

a = AB/AC

   = 10m/s/5s

   = 2 m/s2

This means the graph will be parallel to the time axis intercepting the acceleration axis at 2 m/s2.

From 11 s to 20 s, the car is traveling at the constant velocity of 14 m/s. This means the acceleration of the car is equal to zero. This means the graph will be a straight line coinciding with the time axis in the graph of ax(t).

The following figure shows the corresponding graph of ax(t).

The acceleration is defined as the rate of change of velocity. The slope of vx(t) graph gives acceleration of the object.

Junaid answered 2 years ago
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