A small object moves along the xx-axis with acceleration ax(t)ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At tt = 0the...

Part A

What is the xx-coordinate of the object when tt = 10.0 ss?

Solutions

Expert Solution

genius_generous answered 1 year ago

Next > < Previous

Related Solutions

A small object moves along the xx-axis with acceleration ax(t)ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At tt = 0...

A small object moves along the xx-axis with acceleration ax(t)ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At tt = 0 the object is at xx = -14.0 mm and has velocity v0xv0x = 8.70 m/sm/s. What is the xx-coordinate of the object when tt = 10.0 ss? Express your answer with the appropriate units.

An object moves along the x-axis according to the equation x = 3t ^ 3 - 2t ^ 2 + t along the x-axis.

An object moves along the x-axis according to the equation x = 3t ^ 3 - 2t ^ 2 + t along the x-axis. Find the instantaneous velocity at t = 2 s.A) 29 B) 18 C) 48 D) 43

A small object with mass mm = 0.0900 kg moves along the +x-axis. The only force...

A small object with mass mm = 0.0900 kg moves along the +x-axis. The only force on the object is a conservative force that has the potential-energy function U(x)=−αx2+βx3 where α = 4.50 J/m2 and β = 0.300 J/m3. The object is released from rest at small x. 1-When the object is at x = 4.00 m, what is its speed? Express your answer with the appropriate units. 2-When the object is at x = 4.00 m, what is the...

Consider a 2.0-kgkg object that moves along the x axis according to the expression x(t)=ct3x(t)=ct3, where...

Consider a 2.0-kgkg object that moves along the x axis according to the expression x(t)=ct3x(t)=ct3, where cc = +0.230 m/s3m/s3 . Determine the xx component of the object's average velocity during the interval from titi = 0.500 ss to tftf = 1.50 ss. Use all significant digits provided by your calculator? Repeat for the interval from titi = 0.950 ss to tftf = 1.05 ss. Use all significant digits provided by your calculator? Repeat for the interval from titi =...

An object is at x = 0 at t = 0 and moves along the x...

An object is at x = 0 at t = 0 and moves along the x axis according to the velocity

The only force acting on a 0.5 kg object as it moves along the x axis...

The only force acting on a 0.5 kg object as it moves along the x axis is given by F = (4x i – 3x2y j ) N. where x and y in meter. The object starts moving with velocity of 4 m/s. a) Find the work done by the force as the object moves from x = 1 to x = 3m. b) What is the speed of the object at x = 3 m? please solve a &...

A particle, initially at rest, moves along the x-axis so that its acceleration at any time...

A particle, initially at rest, moves along the x-axis so that its acceleration at any time t ≥ 0 is given by a(t) = 12t2−4 . The position of the particle when t=1 is x(1)=3 . Write an expression for the position x(t) of the particle at any time t ≥ 0.

1D Kinematics Problem: An object moves along the x axis according to the equation x =...

1D Kinematics Problem: An object moves along the x axis according to the equation x = 2.80t2 − 2.00t + 3.00, where x is in meters and t is in seconds. (a) Determine the average speed between t = 2.10 s and t = 3.40 s. (b) Determine the instantaneous speed at t = 2.10 s. Determine the instantaneous speed at t = 3.40 s. (c) Determine the average acceleration between t = 2.10 s and t = 3.40 s....

A 0.150 kg particle moves along an x axis according to x(t) = −13.00 + 2.00t...

A 0.150 kg particle moves along an x axis according to x(t) = −13.00 + 2.00t + 3.50t2 − 2.50t3, with x in meters and t in seconds. In unit-vector notation, what is the net force acting on the particle at t = 3.55 s? F with arrow = ______ N

The function sequals=?f(t) gives the position of an object moving along the? s-axis as a function...

The function sequals=?f(t) gives the position of an object moving along the? s-axis as a function of time t. Graph f together with the velocity function ?v(t)equals=StartFraction ds Over dt EndFractiondsdtequals=f prime left parenthesis t right parenthesisf?(t) and the acceleration function ?a(t)equals=StartFraction d squared s Over dt squared EndFractiond2sdt2equals=f prime prime left parenthesis t right parenthesisf??(t)?, then complete parts? (a) through? (f). sequals=112112tminus?16 t squared16t2?, 0less than or equals?tless than or equals?77 ?(a heavy object fired straight up from? Earth's...

Subjects