A small object moves along the xx-axis with acceleration ax(t)ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At tt = 0...

A small object moves along the xx-axis with acceleration ax(t)ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At tt = 0 the object is at xx = -14.0 mm and has velocity v0xv0x = 8.70 m/sm/s.

What is the xx-coordinate of the object when tt = 10.0 ss?

Express your answer with the appropriate units.

Expert Solution

Use integration to find the velocity using the equation for acceleration and then use the equation for velocity to find the position equation and then put the value of time to find the solution as shown below

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genius_generous answered 1 year ago

A small object moves along the xx-axis with acceleration ax(t)ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At tt = 0the...

A small object moves along the xx-axis with acceleration ax(t)ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At tt = 0the object is at xx = -14.0 mm and has velocity v0xv0x = 4.10 m/sm/s. Part A What is the xx-coordinate of the object when tt = 10.0 ss?

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