In: Advanced Math
Sketch the graph of y = x3 − 3x + 3.
At x-intercepts you must have y=0, hence we need to find the real root of y=0.
. Hence the point (a,y(a)) is the x-intercept of the curve.where -1<a<-3.
At y intercepts, x=0 hence the point (0,3) is the y-intercept.
At the extremum points you must have the derivative of y that is y'=0. Now, y'=3x²-3 &. y"=6x
So y' = 0 implies x = ±1.
at x=1, you will have y=1 and y"= 6 >0 so the point (1,1) is locally minimum.
at x=-1, you get y=5 and y"= -6 < 0, so the point (-1,5) is the point of locally maximum.
And as x± infinity you get, y± infinity.
And from the above information on (x,y) you can draw the curve roughly....