A Ferris Wheel, starting from rest, undergoes a constant angular acceleration of 0.033 rad/s2 to get...

A Ferris Wheel, starting from rest, undergoes a constant angular acceleration of 0.033 rad/s2 to get to its final operating angular velocity of 0.24 rad/s. (a) How long does it take the Ferris Wheel to get to its operating angular velocity? (b) How many revolutions does it make during this time interval?

Expert Solution

Initial angular velocity ₀ = 0 rad/s. Final angular velocity = 0.24 rad/s.

Angular acceleration = 0.033 rad/s².

a) kinematical equation of rotational motion: = ₀ + t

The time to gets it operational angular velocity

t =( – ₀ )/ = ( 0.24–0)/0.033 = 7.27 s

b) Another kinematical equation of rotational motion : = ₀t + 0.5 * *t²

Angular displacement in that time = 0 + 0.5 × 0.033 × (7.27)² = 0.87 radian.

2 π radian displacement = 1 revolution

0.87 radian displacement = 0.87/ 2π = 0.14 revolution

genius_generous answered 2 years ago

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