A wheel turns with a constant angular acceleration of 0.700 rad/s2rad/s2. I JUST NEED PART B...

A wheel turns with a constant angular acceleration of 0.700 rad/s2rad/s2. I JUST NEED PART B , THANK YOU.

part a :

How much time does it take to reach an angular velocity of 6.00 rad/srad/s, starting from rest?

Express your answer in seconds.

Answer=8.57s

part b:

Through how many revolutions does the wheel turn in this interval?

Express your answer as a number of revolutions.

Expert Solution

Since the angular acceleration is uniform, f2=i2+2, where f is final angular velocity, i is initial angular velocity, is angular acceleration, is angular displacement.

So,=(f2-i2)/(2)

Here, i=0 rad/s. f=6 rad/s, =0.7 rad/s2

So, =(62-02)/(2*0.7)=25.71428 radians=25.71428/(2) revolutions=4.09 revolutions.

genius_generous answered 1 year ago

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