In: Economics
Although the increasing popularity of the Southport neighborhood has generally been a very positive development, there are a few negatives associated with it. You already addressed parking concerns. Another serious issue involves criminal activity. Southport has always had low levels of violent crime, and fortunately this doesn't appear to be changing. However, there has been a significant increase in vandalism and graffiti incidents. The police force is already working overtime, but it just can't keep up with the rapid growth.
Because of these issues, the City Council is considering options to increase monitoring and reduce the load on law-enforcement officers. The budget is limited, which means it is important to make a cost-effective decision. The options being considered are described below:
The city has obtained data from other areas regarding the effectiveness of hiring additional officers and installing cameras and lights. The city has estimated that each crime prevented is worth $1,000 to the city (the amount includes the expenses incurred by the police department, courts, and prisons) Each additional police officer would be paid $20,000 per year. Each security camera/light installation would cost $8,000 per year to operate and maintain. A summary of this data is below:
Number of Crimes Prevented Per Year |
Number of Officers Hired |
21 | 1 |
47 | 2 |
76 | 3 |
104 | 4 |
128 | 5 |
149 | 6 |
165 | 7 |
178 | 8 |
188 | 9 |
195 | 10 |
Number of Crimes Prevented Per Year |
Number of Camera/ Light Installations |
6 | 1 |
13 | 2 |
25 | 3 |
33 | 4 |
40 | 5 |
Write a 300- to 500-word report to John Becker. In your report, be sure to
Number of crimes prevented per year | Number of officers hired | $ Revenue | Marginal Revenue | $ Cost | Marginal Product |
21 | 1 | 21000 | 20000 | ||
47 | 2 | 47000 | 26000 | 40000 | 20000 |
76 | 3 | 76000 | 71300 | 60000 | 20000 |
104 | 4 | 104000 | 28000 | 80000 | 20000 |
128 | 5 | 128000 | 24000 | 100000 | 20000 |
149 | 6 | 149000 | 21000 | 120000 | 20000 |
165 | 7 | 165000 | 16000 | 140000 | 20000 |
178 | 8 | 178000 | 13000 | 160000 | 20000 |
188 | 9 | 188000 | 10000 | 180000 | 20000 |
195 | 10 | 195000 | 7000 | 200000 | 20000 |
Number of crimes prevented per year | Number of lights/cameras installed per year | $ Revenue | Marginal Revenue | $ Cost | Marginal Cost |
6 | 1 | 6000 | 8000 | ||
13 | 2 | 13000 | 7000 | 16000 | 8000 |
25 | 3 | 25000 | 12000 | 24000 | 8000 |
33 | 4 | 33000 | 8000 | 32000 | 8000 |
40 | 5 | 40000 | 7000 | 40000 | 8000 |
The revenue earned by the authorites for each crime prevented in $1000. Thus revenue is calculated by multiplying the crimes by 1000
the cost paid by the authorities to appoint each police officer is $20000. Thus the product/cost of the police officers has been calculated by multipying the number of officers recruited by 20000
the cost to install lights and cameras is $8000. Thus the product /cost of the cameras and lights has been calculated by multiplying the number of installations by 8000
The marginal revenue is calculated by Existing Revenue - The older Revenue in simple terms.
The marginal cost l product is calculated in the same way by reducing the older product from the existing product.
By observing the above calculated tables.:
1 More crimes might be prevented by recruiting more police officers because, even though the cost of recruiting the officers is more, the number of crimes prevented and thus the revenue earned thereof is also more.
2. If only police officers are recruited, the optimal number of police officers to be recruited is 6 as the average of marginal revenue as well as the cost is optimal at that level.
3. If only cameras and lights have to be installed then the optimal number of lights and cameras to be installed will be 2 as the average of marginal revenue is the same at 2 cameras as well as 5 cameras but the considering the cost incurred 2 cameras is the best cost as both 2 cameras and 5 cameras yield the same revenue.