In: Statistics and Probability
Operator takes a sample of 3 tablets once per hour and measures their weights. Data for the first 10 hours is shown below.
| 
 Time (hr)  | 
 Weight-1  | 
 Weight-2  | 
 Weight-3  | 
| 
 0  | 
 253.31  | 
 246.03  | 
 253.57  | 
| 
 1  | 
 247.97  | 
 248.31  | 
 251.57  | 
| 
 2  | 
 249.47  | 
 250.04  | 
 250.15  | 
| 
 3  | 
 248.38  | 
 247.74  | 
 254.81  | 
| 
 4  | 
 250.55  | 
 241.08  | 
 251.35  | 
| 
 5  | 
 242.40  | 
 248.07  | 
 250.43  | 
| 
 6  | 
 254.59  | 
 247.63  | 
 252.42  | 
| 
 7  | 
 248.38  | 
 252.33  | 
 252.61  | 
| 
 8  | 
 256.07  | 
 248.46  | 
 254.95  | 
| 
 9  | 
 245.84  | 
 250.97  | 
 247.68  | 
Answer :- Operator takes a sample of 3 tablets, once per hour and measures their weight.
=> To construct X̄ and R chart for tablet weight for the given data :-

Given data :-
• m = 10
• n = 3
=> X̄ = ∑X̄i /m
= 2499.0533 /10
[ X̄ = 249.9053 ]
=> R bar = ∑Ri /m
= 61.12/10
[ 6.112 ]
• The control Limits for X̄ chart is :-
Hear we take : [ A2 = 1.023 for n = 3 ]
=> Upper Control Limit = X̄ + (A2) (R bar)
=> UCL = 249.9053 + (1.023) (6.112)
= 249.9053 + 6.2525
= 256.1578
[ UCL = 256.16 ]
[ CL = 249.90 ]
=> Lower Control Limit = X̄ - (A2)(R bar)
=> LCL = 249.9053 - (1.023) (6.112)
= 249.9053 - 6.2525
= 243.6528
[ LCL = 243.65 ]
• The control Limits for R chart is :-
Here we take ( D4 = 2.575 for n = 3 )
=> Upper Control Limit = D4 (R bar)
=> UCL = 2.575 × 6.112
= 15.7384
[ UCL = 15.74 ]
CL = 6.112 ~ [ CL = 6.11 ]
=> Lower Control Limit = D3 (R bar)
Here (D3 = 0 for n =3)
=> LCL = (0) (6.112)
= 0
[ LCL = 0 ]
Conclusion :-
• X̄ chart :- The process is in control because all the points in X̄ chart is above Lower Control Limit and below Upper Control Limit.
• R-chart :- The process is in control because all the points in R-chart is above Lower Control Limit and below Upper Control Limit.

