In: Statistics and Probability
Operator takes a sample of 3 tablets once per hour and measures their weights. Data for the first 10 hours is shown below.
Time (hr) |
Weight-1 |
Weight-2 |
Weight-3 |
0 |
253.31 |
246.03 |
253.57 |
1 |
247.97 |
248.31 |
251.57 |
2 |
249.47 |
250.04 |
250.15 |
3 |
248.38 |
247.74 |
254.81 |
4 |
250.55 |
241.08 |
251.35 |
5 |
242.40 |
248.07 |
250.43 |
6 |
254.59 |
247.63 |
252.42 |
7 |
248.38 |
252.33 |
252.61 |
8 |
256.07 |
248.46 |
254.95 |
9 |
245.84 |
250.97 |
247.68 |
Answer :- Operator takes a sample of 3 tablets, once per hour and measures their weight.
=> To construct X̄ and R chart for tablet weight for the given data :-
Given data :-
• m = 10
• n = 3
=> X̄ = ∑X̄i /m
= 2499.0533 /10
[ X̄ = 249.9053 ]
=> R bar = ∑Ri /m
= 61.12/10
[ 6.112 ]
• The control Limits for X̄ chart is :-
Hear we take : [ A2 = 1.023 for n = 3 ]
=> Upper Control Limit = X̄ + (A2) (R bar)
=> UCL = 249.9053 + (1.023) (6.112)
= 249.9053 + 6.2525
= 256.1578
[ UCL = 256.16 ]
[ CL = 249.90 ]
=> Lower Control Limit = X̄ - (A2)(R bar)
=> LCL = 249.9053 - (1.023) (6.112)
= 249.9053 - 6.2525
= 243.6528
[ LCL = 243.65 ]
• The control Limits for R chart is :-
Here we take ( D4 = 2.575 for n = 3 )
=> Upper Control Limit = D4 (R bar)
=> UCL = 2.575 × 6.112
= 15.7384
[ UCL = 15.74 ]
CL = 6.112 ~ [ CL = 6.11 ]
=> Lower Control Limit = D3 (R bar)
Here (D3 = 0 for n =3)
=> LCL = (0) (6.112)
= 0
[ LCL = 0 ]
Conclusion :-
• X̄ chart :- The process is in control because all the points in X̄ chart is above Lower Control Limit and below Upper Control Limit.
• R-chart :- The process is in control because all the points in R-chart is above Lower Control Limit and below Upper Control Limit.