In: Statistics and Probability
Jill is studying the weights of adult dogs and takes a random sample from 3 populations. Jill wants to know if the 3 breeds of dogs all hae the same population mean weight. She takes a random sample from each population and will do an ANOVA test
Bulldogs { 54, 58, 44, 46, 62, 60 }
Greyhounds { 68, 59, 65, 47, 71, 62 }
Keeshonds { 64, 58, 66, 52, 50 }
a.)What is Bob’s null and alternative hypothesis?
b.)Find the sample size, sample mean, and sample variance of all three samples.
c.) Find the over all sample mean
d.) Find SSA, SSE, MSA, MSE, test statisitc F. Draw ANOVA table
e.) Draw a picture of the rejection region ( alpha=0.5) on the appropriate curve and identify the critical value
f.)whats Jills conclusion
g.) what assumptions, if any, were required to complete this hypothesis test
a)
Ho: µ1=µ2=µ3
H1: not all means are equal
b)
treatment | A | B | C |
count, ni = | 6 | 6 | 5 |
mean , x̅ i = | 54.000 | 62.00 | 58.000 |
std. dev., si = | 7.483 | 8.485 | 7.071 |
sample variances, si^2 = | 56.000 | 72.000 | 50.000 |
c) grand mean , x̅̅ = Σni*x̅i/Σni = 58.00
d)
treatment | A | B | C | |||
SS(between)= SSB = Σn( x̅ - x̅̅)² = | 96.000 | 96.000 | 0.000 | 192 | ||
SS(within ) = SSW = Σ(n-1)s² = | 280.000 | 360.000 | 200.000 | 840.0000 |
SSA=192
SSE=840
mean square between groups , MSA = SSA/k-1 =
96.0000
mean square within groups , MSE = SSE/N-k =
60.0000
F-stat = MSA/MSE =
1.6000
anova table | ||||||
SS | df | MS | F | p-value | F-critical | |
Between: | 192.000 | 2 | 96.000 | 1.600 | 0.2367 | 3.739 |
Within: | 840.000 | 14 | 60.000 | |||
Total: | 1032.000 | 16 | ||||
α = | 0.05 |
e) critical value = 3.739
Decision: reject Ho
f)
three assumptions for ANOVA analysis, namely, independence,
equal variance, and normality.