Question

In: Statistics and Probability

Jill is studying the weights of adult dogs and takes a random sample from 3 populations....

Jill is studying the weights of adult dogs and takes a random sample from 3 populations. Jill wants to know if the 3 breeds of dogs all hae the same population mean weight. She takes a random sample from each population and will do an ANOVA test

Bulldogs { 54, 58, 44, 46, 62, 60 }

Greyhounds { 68, 59, 65, 47, 71, 62 }

Keeshonds { 64, 58, 66, 52, 50 }

a.)What is Bob’s null and alternative hypothesis?

b.)Find the sample size, sample mean, and sample variance of all three samples.

c.) Find the over all sample mean

d.) Find SSA, SSE, MSA, MSE, test statisitc F. Draw ANOVA table

e.) Draw a picture of the rejection region ( alpha=0.5) on the appropriate curve and identify the critical value

f.)whats Jills conclusion

g.) what assumptions, if any, were required to complete this hypothesis test

Solutions

Expert Solution

a)

Ho: µ1=µ2=µ3
H1: not all means are equal

b)

treatment A B C
count, ni = 6 6 5
mean , x̅ i = 54.000 62.00 58.000
std. dev., si = 7.483 8.485 7.071
sample variances, si^2 = 56.000 72.000 50.000

c) grand mean , x̅̅ =    Σni*x̅i/Σni =                 58.00

d)

treatment A B C
SS(between)= SSB = Σn( x̅ - x̅̅)² = 96.000 96.000 0.000 192
SS(within ) = SSW = Σ(n-1)s² = 280.000 360.000 200.000 840.0000

SSA=192

SSE=840

mean square between groups , MSA = SSA/k-1 =    96.0000
  
mean square within groups , MSE = SSE/N-k =    60.0000

F-stat = MSA/MSE =    1.6000

anova table
SS df MS F p-value F-critical
Between: 192.000 2 96.000 1.600 0.2367 3.739
Within: 840.000 14 60.000
Total: 1032.000 16
α = 0.05

e) critical value = 3.739

Decision: reject Ho

f)

three assumptions for ANOVA analysis, namely, independence, equal variance, and normality.


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