A random sample of voters is surveyed to find out if they feel that votes in...

A random sample of voters is surveyed to find out if they feel that votes in Florida should be recounted. The contingency table below shows their opinions and their party affiliation. Can you conclude (using alpha=.1) that party affiliation is independent of a voter’s opinion?

Party Affiliation

Opinion	Republican	Democrat	Independent
Should recount	120	200	22
Should not recount	200	110	30
No opinion	10	50	118

Expert Solution

orchestra answered 1 year ago

A public opinion poll surveyed a simple random sample of 550 voters in Oregon. The respondents...

A public opinion poll surveyed a simple random sample of 550 voters in Oregon. The respondents were asked which political party they identified with most and were categorized by residence. Results are shown below. Decide if voting preference is independent from location of residence. Let α=0.05. Republican Democrat Independent NW Oregon 85 103 22 SW Oregon 45 66 10 Central Oregon 46 53 9 Eastern Oregon 67 33 11 Enter the test statistic - round to 4 decimal places.

A public opinion poll surveyed a simple random sample of 1000 voters. Respondents were classified by...

A public opinion poll surveyed a simple random sample of 1000 voters. Respondents were classified by gender (male or female) and by voting preference (Republican, Democrat, or Independent). Results are shown in the contingency table below. VOTING PREFERENCES Rep Dem Ind Row Total Male 350 075 25 450 Female 275 240 35 550 Column Total 625 315 60 1000 Is there a gender gap? D3 the men's voting preferences differ significantly from the women's preferences? Use...

1. In a presidential election, 308 out of 611 voters surveyed said that they voted for...

1. In a presidential election, 308 out of 611 voters surveyed said that they voted for the candidate who won. Use a 0.01 significance level to test that among all voters, the percentage who believe they voted for the winning candidate is different from 43%, which is the actual percentage of votes for the winning candidate. What does the result suggest about voter perceptions? Must show all work.

In a random sample of 50 voters, intended to show that more voters are in favor...

In a random sample of 50 voters, intended to show that more voters are in favor of candidate A, 34 said they favor candidate A. (a) What is the probability that this many or more voters would favor A is the true proportion of all eligible voters favoring A is 0.54? (b) Is the result significant at the 0.05 level? What about the 0.01 level? Explain your answers.

A sample poll of 100 voters chosen at random from all voters in a given school...

A sample poll of 100 voters chosen at random from all voters in a given school district indicated that 53% of them were in favor of a 1% increase in property taxes in order to provide funds to hire more teachers. a. Find the 95% confidence interval for the population proportion of voters supporting the property tax hike? b. Can we be confident that the tax hike will pass given your results in part (a)? Explain....

Pollsters at Quinnipiac University surveyed 751 likely New York voters and found out that 368 of...

Pollsters at Quinnipiac University surveyed 751 likely New York voters and found out that 368 of 751 are going to vote for Candidate A rather than Candidate B. At the 95 percent confidence level, can a winner be predicted? What is the margin of error? What is the probability of error? What sample size is necessary in order to change the margin of error to 2 percent while leaving the probability of error the same?

According to a poll, 85% of California adults (429 out of 506 surveyed) feel that education...

According to a poll, 85% of California adults (429 out of 506 surveyed) feel that education is one of the top issues facing California. We wish to construct a 90% confidence interval for the true proportion of California adults who feel that education is one of the top issues facing California. What is a point estimate for the true population proportion?

According to a poll, 78% of California adults (397 out of 506 surveyed) feel that education...

According to a poll, 78% of California adults (397 out of 506 surveyed) feel that education is one of the top issues facing California. We wish to construct a 90% confidence interval for the true proportion of California adults who feel that education is one of the top issues facing California. What is a point estimate for the true population proportion?

A random sample of 25 people is surveyed, and it was found that they spent an...

A random sample of 25 people is surveyed, and it was found that they spent an average of 32 hours a week watching TV. The standard deviation of their sample was 6 hours. (a) Calculate a 95% confidence interval for the average number of hours spent watching TV per week (population mean µ - using two-tailed distribution). (b) What is the 95% confidence interval for the single 26th person to be surveyed? (c) What is the 95% confidence interval (two-sided...

Human Resource Consulting (HRC) surveyed a random sample of 53 Twin Cities construction companies to find...

Human Resource Consulting (HRC) surveyed a random sample of 53 Twin Cities construction companies to find information on the costs of their health care plans. One of the items being tracked is the annual deductible that employees must pay. The Minnesota Department of Labor reports that historically the mean deductible amount per employee is $501 with a standard deviation of $102. 1. Point vs. Interval Estimation Here you will discuss the importance of constructing confidence intervals for the population mean....

Question