In: Economics
Compare two alternatives, A and B on the basis of a present worth evaluation using i=8% per year and study period of 8 years. Which alternative should be selected based on PW calculation and what is the PW value of the selected alternative?
Show work for both alternatives. No excel.
|
Alternative |
A |
B |
|
First cost, $ |
-15,000 |
-28,000 |
|
Annual operating cost |
-6,000 |
-9,000 |
|
Overhaul in year 4 |
- |
-2,000 |
|
Salvage value |
3,000 |
5,000 |
|
Life, Years |
4 |
8 |
| Alternative-A | |||||||
| Year | Cashflows | PVF @8% | Present value | ||||
| 0 | 15000 | 1.000 | 15000 | ||||
| 1 | 6000 | 0.926 | 5555.556 | ||||
| 2 | 6000 | 0.857 | 5144.033 | ||||
| 3 | 6000 | 0.794 | 4762.993 | ||||
| 4 | 18000 | 0.735 | 13230.54 | ||||
| 5 | 6000 | 0.681 | 4083.499 | ||||
| 6 | 6000 | 0.630 | 3781.018 | ||||
| 7 | 6000 | 0.583 | 3500.942 | ||||
| 8 | 3000 | 0.540 | 1620.807 | ||||
| Present value of cash outflows | 56,679 | ||||||
| Note: In year 4, the salvage will realise and new investment of $15,000 to be made | |||||||
| Alternative-B | |||||||
| Year | Cashflows | PVF @8% | Present value | ||||
| 0 | 28000 | 1.000 | 28000 | ||||
| 1 | 9000 | 0.926 | 8333.333 | ||||
| 2 | 9000 | 0.857 | 7716.049 | ||||
| 3 | 9000 | 0.794 | 7144.49 | ||||
| 4 | 9000 | 0.735 | 6615.269 | ||||
| 5 | 9000 | 0.681 | 6125.249 | ||||
| 6 | 9000 | 0.630 | 5671.527 | ||||
| 7 | 9000 | 0.583 | 5251.414 | ||||
| 8 | 4000 | 0.540 | 2161.076 | ||||
| Present value of cash outflows | 77,018 | ||||||
| Note: salvage value is deducted at the end of Year -8 | |||||||
| Hence, Alternative A shall be selected as Present value of outflow is $56,679 | |||||||