Question

In: Physics

During a tennis match, a player serves the ball at 28.6 m/s, with the center of...

During a tennis match, a player serves the ball at 28.6 m/s, with the center of the ball leaving the racquet horizontally 2.33 m above the court surface. The net is 12.0 m away and 0.900 m high. When the ball reaches the net, (a) what is the distance between the center of the ball and the top of the net? (b) Suppose that, instead, the ball is served as before but now it leaves the racquet at 5.00° below the horizontal. When the ball reaches the net, what now is the distance between the center of the ball and the top of the net? Enter a positive number if the ball clears the net. If the ball does not clear the net, your answer should be a negative number. Use g=9.81 m/s2.

Solutions

Expert Solution

As the ball is initially serves horizontally we have x component of initial velocity but there is no initial horizontal velocity component

From given deta we can find time taken to reach the ball to the net and considering vartical motion we can find the final separation of the ball and net.


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