In: Chemistry
The purge stream may be used to replace a portion of the methane burned in the reformer. Assuming that the purge gas is at 35°C and that it is fed directly to the reformer burners with 5% excess air at 300°C, how much heat would be released per 100 kmol of purge gas? Estimate the savings ($ per kmol of purge gas) if the purge stream is used in place of natural gas for fuel. (Take $3 per million Btu as the approximate cost of natural gas.)
Given purge stream composition -
CH4- 6.4 %
CO2-6.3 %
CO- 6.8 %
H2- 78.7 %.
Please note that CO2 here will not combust further because carbon is alreaday in it\'s highest oxidation state possible here.
Following reaction will take place here-
CH4+ 2O2 - CO2+2H2O
CO+0.5O2 - CO2
H2+0.5O2 - H2O
for 100 moles of the purge gas.
Moles of CH4 = 6.4 moles
Moles of CO = 6.8 %
Moles of H2 = 78.7 %
We can take the data for the heat of combustion of these three reactions from the literature.
Heat of combustion of CO = - 283 kJ/mole
Heat of combustion of H2 = - 241.8 kJ/mole
Heat of combustion of CH4 = -217 kJ/mole
Please note that here negative sign is indicating that the heat is getting released.
Total heat released = 283*8.6 kJ +241.8*78.7 kJ + 217*6.4 kJ
=22852 kJ
Amount of the purge gas that is being used = 46.8 kmol/h
= 46800 moles/hr
For 1 hour
heat released by using 100 moles purge gas = 22852 kJ
Heat released by using this purge gas = (46800/100)*22852 kJ
= 10694736 kJ
1 Btu =1.055 kJ
Heat released = (10694736 kJ )/(1.055 kJ/Btu)
= 10137190 Btu
= 10.13 Million Btu or approximately 10 Btu.
Saving if this purge stream is used in place of natural gas is 3$ per Btu.
Total savings = 3*10 $
= 30 $
Since we have done this calculation for 1 hour, savings will be reported as 30 $ per hour.
Since we have done this calculation for 1 hour, savings will be reported as 30 $ per hour.