In: Statistics and Probability
An inspector is doing a quality control assessment on a new shipment of wireless headphones. The original invoices for the headphones show 35% of their supply is from the Jabra company and 65% is from the Samsung company. The inspector also knows that Jabra’s headphones have a 3% defect rate (meaning that 3% of the sample will fail on first usage). The defect rate for Samsung headphones is estimated at 4%.
Complete each subquestion that follows, showing all of your work either in this screen OR compiled into a separate word/excel document and submitted to the Scratch work dropbox. Further, clearly note each subquestion you answer.
We are given here that: 35% of their supply is from the Jabra
company and 65% is from the Samsung company. Therefore,
P(J) = 0.35, and P(S) = 0.65
The inspector also knows that Jabra’s headphones have a 3%
defect rate (meaning that 3% of the sample will fail on first
usage). The defect rate for Samsung headphones is estimated at 4%.
Therefore, we have here:
P(D | J) = 0.03,
P(D | S) = 0.04
The two events of interest here are:
a) From which company is the supply from - Jabra or
Samsung
b) Whether the headphone is defective or not.
The probability notations are already described above as:
P(J) = 0.35, and P(S) = 0.65
P(D | J) = 0.03,
P(D | S) = 0.04
The other probabilities that could be derived here are given as:
P(ND | J) = 1 - P(D | J) = 1 - 0.03 = 0.97, which is the
probability of a non defective headphone given a Jabra headphone is
selected.
P(ND | S) = 1 - P(D | S) = 1 - 0.04 = 0.96, which is the
probability of a non defective headphone given a Samsung headphone
is selected.
The Tree Diagram here is given as:
Now the probability of a randomly selected pair of headphones from this supply being Jabra brand and failing on first use is computed using Bayes theorem here as:
P(J and D) = P(D | J)P(J) = 0.03*0.35 = 0.0105
Therefore 0.0105 is the required probability here.
Now using addition law of probability, we have here:
P(D) = P(D | J)P(J) + P(D | S)P(S) = 0.0105 + 0.65*0.04 =
0.0365
Therefore, P(ND) = 1 - P(D) = 1 - 0.0365 = 0.9635
Therefore the probability of a randomly selected pair of headphones from this supply not failing upon first use is given as 0.9635