Question

In: Statistics and Probability

An instructor is interested in seeing if there is an association between attendance and final grade...

An instructor is interested in seeing if there is an association between attendance and final grade earned in a freshman level class. He records the number of absences for each student and then whether they pass or fail the class. The results are summarized below.

Number of Absences
0-3 4-6 7+ Total
Total 135 66 29 230
Fail 28 19 23 70
Total 163 85 52 300

Construct a 99% confidence interval for the true proportion of students who pass the class Round your sample statistic and confidence limits to three decimal places.
0.
1.
2.

3.

4.

5.

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b. At a 0.01 significance level, can the instructor conclude that there is a relationship between number of absences and whether the student passes or fails the class? (Note: Round expected counts to the nearest whole number)
1.
2.
3.
4.
5.

Solutions

Expert Solution

Answer:

(a)

Step 1:

n = Sample Size = 300

= Sample Proportion = 230/300 = 0.767

Step 2:

= 0.01

From Table, critical values of Z = 2.576

Step 3:

Confidence Interval:

So,

Answer is:

(0.704, 0.830)

(b)

Step !

H0: Null Hypothesis: There is no relationship between number of absentees and whether the student passes or fails the class.

HA: Alternative Hypothesis: There is a relationship between number of absentees and whether the student passes or fails the class.

Step 2:

Expected Frequencies are got as follows (AS REQUIRED IN THE QUESTION: Round expected counts to the nearest whole number):;

0-3 4-6 7+ Total
Pass 163 X 230/ 300 = 125 85 X 230/ 300 = 65 52 X 230/ 300 = 40 230
Fail 163 X 70/ 300 = 38 85 X 70/ 300 = 20 52 X 70/ 300 = 12 70
Total 163 85 52 300

Step 3:

Test Statistic () is got as follows:

Observed (O) Expected (E) (O - E)2/E
135 125 0.800
66 65 0.015
29 40 3.025
28 38 2.632
19 20 0.050
23 12 10.083
Total = = 16.605

Step 4:

= 0.01

df = (r - 1) X (c - 1) = (2 - 1) X (3 - 1) = 2

From Table, critical value of = 9.2103

Since calculated value of = 16.605 is greatr than critical value of = 9.2103, the difference is significant. Reject null hypothesis.

Conclusion:
The data supports the claim that there is a relationship between number of absentees and whether the student passes or fails the class.

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