In: Statistics and Probability
An instructor is interested in seeing if there is an association between attendance and final grade earned in a freshman level class. He records the number of absences for each student and then whether they pass or fail the class. The results are summarized below.
0-3 | 4-6 | 7+ | Total | |
Total | 135 | 66 | 29 | 230 |
Fail | 28 | 19 | 23 | 70 |
Total | 163 | 85 | 52 | 300 |
Construct a 99% confidence interval for the true proportion of
students who pass the class Round your sample statistic and
confidence limits to three decimal places.
0.
1.
2.
3.
4.
5.
ÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞÞ
b. At a 0.01 significance level, can the instructor conclude
that there is a relationship between number of absences and whether
the student passes or fails the class? (Note: Round expected counts
to the nearest whole number)
1.
2.
3.
4.
5.
Answer:
(a)
Step 1:
n = Sample Size = 300
= Sample Proportion = 230/300 = 0.767
Step 2:
= 0.01
From Table, critical values of Z = 2.576
Step 3:
Confidence Interval:
So,
Answer is:
(0.704, 0.830)
(b)
Step !
H0: Null Hypothesis: There is no relationship between number of absentees and whether the student passes or fails the class.
HA: Alternative Hypothesis: There is a relationship between number of absentees and whether the student passes or fails the class.
Step 2:
Expected Frequencies are got as follows (AS REQUIRED IN THE QUESTION: Round expected counts to the nearest whole number):;
0-3 | 4-6 | 7+ | Total | |
Pass | 163 X 230/ 300 = 125 | 85 X 230/ 300 = 65 | 52 X 230/ 300 = 40 | 230 |
Fail | 163 X 70/ 300 = 38 | 85 X 70/ 300 = 20 | 52 X 70/ 300 = 12 | 70 |
Total | 163 | 85 | 52 | 300 |
Step 3:
Test Statistic () is got as follows:
Observed (O) | Expected (E) | (O - E)2/E |
135 | 125 | 0.800 |
66 | 65 | 0.015 |
29 | 40 | 3.025 |
28 | 38 | 2.632 |
19 | 20 | 0.050 |
23 | 12 | 10.083 |
Total = = | 16.605 |
Step 4:
= 0.01
df = (r - 1) X (c - 1) = (2 - 1) X (3 - 1) = 2
From Table, critical value of = 9.2103
Since calculated value of = 16.605 is greatr than critical value of = 9.2103, the difference is significant. Reject null hypothesis.
Conclusion:
The data supports the claim that there is a relationship between
number of absentees and whether the student passes or fails the
class.
NOTE:: I HOPE THIS ANSWER IS HELPFULL TO YOU......**PLEASE SUPPORT ME WITH YOUR RATING......
**PLEASE GIVE ME "LIKE".....ITS VERY IMPORTANT FOR,ME......PLEASE SUPPORT ME .......THANK YOU