A particle (mass = 6.7 x 10-27 kg, charge = 3.2 x 10-19 C) moves along...

A particle (mass = 6.7 x 10-27 kg, charge = 3.2 x 10-19 C) moves along the positive x axis with a speed of 4.1 x 105 m/s. It enters a region of uniform electric field parallel to its motion and comes to rest after moving 5.0 m into the field. What is the magnitude of the electric field (in N/C) ?

Solutions

Expert Solution

Mass of the particle

Charge of the particle

Initial speed of the particle

Finally the particle comes to rest, final velocity of the particle is

Let E be the electric field, the force on the particle is F=qE

Work done by the electric field in displacing the particle by amount d=5.0m is

By work-energy theorem, the net work done on a particle is equal to the change in kinetic energy of the particle

Using

The magnitude of the electric field is

Substituting values

genius_generous answered 1 year ago

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