Question
In: Chemistry
Given the following reactions: COBr2 (g) --------------- > CO (g) + Br2 (g) K = .190...
Given the following reactions:
COBr2 (g) --------------- > CO (g) + Br2 (g) K = .190 at 73 °C
2 BrCl (g) ------------ > Br2 (g) + Cl2 (g) K = 310 at 73 °C (estimated)
Find the equilibrium constant at 73 °C for: CO + BrCl ------- > COBr2 + Cl2
Solutions
Expert Solution
Find the equilibrium constant at 73 °C for: CO + BrCl ------- > COBr2 + Cl2
COBr2 (g) --------------- > CO (g) + Br2 (g) K = .190 at 73 °C---1
2 BrCl (g) ------------ > Br2 (g) + Cl2 (g) K = 310 at 73 °C---2
CO + BrCl ------- > COBr2 + Cl2
To find the above reaction reverse the eq 1.
CO (g) + Br2 (g) --------------- > COBr2 (g) K’= 1/K=1/0.190=5.36 ---3
On reversing the equation new equilibrium constant is 1/K
Now add eq 2 and 3
CO (g) + Br2 (g) --------------- > COBr2 (g)
2 BrCl (g) ------------ > Br2 (g) + Cl2 (g)
CO + 2BrCl ------- > COBr2 + Cl2
To add equation equilibrium constant are multiplied
K = 5.36 *310
K= 1661.6
queen_honey_blossom answered 1 year agoRelated Solutions
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Express your answer in molarity to three significant
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[CO]=
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M
SubmitRequest Answer
Part B
What...
For the following reaction, Kc = 255 at 1000 K. CO (g) + Cl2 (g) ⇌...
For the following reaction, Kc = 255 at 1000 K.
CO (g) + Cl2 (g) ⇌ COCl2 (g)
A reaction mixture initially contains a COconcentration of 0.1470
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Part a. What is the equilibrium concentration of CO at 1000
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Part B:What is the equilibrium concentration of Cl2 at 1000
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Part C:What is the equilibrium concentration of COCl2 at 1000
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or the following reaction, Kc = 255 at 1000 K. CO (g) + Cl2 (g) ⇌...
or the
following reaction, Kc = 255 at 1000 K.
CO (g) + Cl2 (g) ⇌ COCl2 (g)
You may want to reference (Pages 693 - 702)Section 15.8 while
completing this problem.
Part A
If a reaction mixture initially contains a CO concentration of
0.1470 and a Cl2 concentration of 0.180 at 1000K. What is the
equilibrium concentration of CO at 1000 K?
Express your answer in molarity to three significant
figures.
[CO]=
nothing
M
SubmitRequest Answer
Part B
What...
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