What is the pH of a 8.6 x 10-8 M solution of HCl(aq) at 25 °C? Report your answer to the hundredths place. Assuming complete dissociation, what is the pH of a 3.98 mg/L Ba(OH)2 solution?Arrange the aqueous solutions from the most acidic to the most basic, at 25 °C. Each value represents a different aqueous solution at 25°C. Acidic Basic each solution as acidic, basic, or neutral.
Calculate the pH at 25°C of a 0.94 M solution of
lidocaine HCL (C14H21NONH2Cl). Note that lidocaine is a weak base
with a PKB of 7.94. Round answer to 1 decimal place.
1) Calculate the pH of the resulting solution if 35.0 mL of
0.350 M HCl(aq) is added to 40.0 mL of 0.350 M NaOH(aq) .
2) Calculate the pH of the resulting solution if 35.0 mL of
0.350 M HCl(aq) is added to 45.0 mL of 0.400 M NaOH(aq) .
Calculate the pH of the resulting solution if 35.0 mL of 0.350 M
HCl(aq) is added to
(a) 45.0 mL of 0.350 M NaOH(aq).
pH=
(b) 25.0 mL of 0.450 M NaOH(aq).
pH=
What is the pH of a 1.3 x 10-7 M solution of HCl? Please note
that you cannot simply add the contribution of H+ ions from the
autoproteolysis of water and the contribution from the dissociation
of HCl. You will need to use the quadratic equation to solve this
problem and report the answer to 4 significant figures.