In: Statistics and Probability
1.09 0.88 0.52 1.48 1.38 1.27 0.64 1.77 1.41 1.11
First we need to find the mean and SD of data set. Following table shows the calculations:
X | (X-mean)^2 | |
1.09 | 0.004225 | |
0.88 | 0.075625 | |
0.52 | 0.403225 | |
1.48 | 0.105625 | |
1.38 | 0.050625 | |
1.27 | 0.013225 | |
0.64 | 0.265225 | |
1.77 | 0.378225 | |
1.41 | 0.065025 | |
1.11 | 0.002025 | |
Total | 11.55 | 1.36305 |
Since confidence interval contains 1.25 so 1.25 is a reasonable possibility for the true mean value.
(b)
Since there 10 data values in the sample so degree of freedom is
df=10-1=9 and critical value of t for 95% confidence interval,
using excel function "=TINV(0.05,9)" is 2.262.
The 95% prediction interval is
Hence,
(c)
Value of k for 90% tolerance interval and 95% confidence interval is 2.839.
So requried tolerance interval is