In: Statistics and Probability
Anystate Auto Insurance Company took a random sample of 386
insurance claims paid out during a 1-year period. The average claim
paid was $1550. Assume σ = $230.
Find a 0.90 confidence interval for the mean claim payment. (Round
your answers to two decimal places.)
lower limit | $ |
upper limit | $ |
Find a 0.99 confidence interval for the mean claim payment. (Round
your answers to two decimal places.)
lower limit | $ |
upper limit | $ |
Solution :
Given that,
a) Z/2 = Z0.05 = 1.645
Margin of error = E = Z/2
* (
/n)
= 1.645 * ( 230 / 386
)
= 19.26
At 90% confidence interval estimate of the population mean is,
± E
= 1550 ± 19.26
= ( 1530.74, 1569.26 )
lower limit = $ 1530.74
upper limit = $ 1569.26
b) Z/2 = Z0.005 = 2.576
Margin of error = E = Z/2
* (
/n)
= 2.576 * ( 230 / 386
)
= 30.16
At 99% confidence interval estimate of the population mean is,
± E
= 1550 ± 30.16
= ( 1519.84, 1580.16 )
lower limit = $ 1519.84
upper limit = $ 1580.16