In: Statistics and Probability
A simple random sample of size n is drawn. The sample mean, x is found to be 19.3 and the sample standard deviation, s, is found to be 4.7
a. Construct a 95% confidence interval about mu if the sample size, n, is 35
solution
Given that,
= 19.3
s =4.7
n = 35
Degrees of freedom = df = n - 1 = 35- 1 = 34
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
t /2,df = t0.025,34 = 2.032 ( using student t table)
Margin of error = E = t/2,df * (s /n)
= 2.032* ( 4.7/ 35) = 1.6143
The 95% confidence interval estimate of the population mean is,
- E < < + E
19.3 - 1.6143 < < 19.3+ 1.6143
17.6857 < < 20.9143
( 17.6857 ,20.9143)