In: Statistics and Probability
A simple random sample of size n is drawn. The sample mean is found to be 17.6, and the sample standard deviation, s, is found to be 4.7.
A). Construct a 95% confidence interval about if the sample size, n, is 51.
We have given that,
Sample mean =17.6
Sample standard deviation =4.7
Sample size =51
Level of significance=1-0.95=0.05
Degree of freedom =50
t critical value is (by using t table)=
2.01
Confidence interval formula is
=(16.28,18.92)
Lower confidence limit= 16.28
Upper confidence limit= 18.92