In: Physics
given, speaker A is at origin, B is at (3,0)
everything is in xy plane, measures in meters
Given, speakers are the same
consider point P(1,4)
a. the time graphs are given for f = 500 Hz
b.
speed of sound, v = 350 m/s
B is phase pi/4 after A
now phase of 2*pi corresponds to wavelenth lambda
hence pi/4 corresponds to lambda/8
so speaker A leads speaker B wavelength by lamdba/8 [where lamdba
is wavelength of both the speakers as bot are same speakers at same
frequency]
so, for constructive interference,
path difference should be 0 at point P
now actual difference in PA and PB
PA - PB = sqrt(1 + 16) - sqrt((1 - 3)^2 + (4 - 0)^2) = sqrt(17) -
sqrt(20)
PA - PB = -0.34903032938 m
so for constructive interference
0.34903032938 = lambda/8 + n*lambda
now, lambda*f = v
hence ,
f = v[1 + 8n] /0.34903032938*8
for three lowest frequencies
n = 0, 1, 2
f = 350[1 + 8n] /0.34903032938*8 = 125.34727(1 + 8n)
f0 = 125.34727 Hz
f1 = 1128.1254 Hz
f2 = 2130.9036 Hz
c.for destructive interfernece
0.34903032938 = lambda/8 + n*lambda/2 [ n = 1, 3, 5, n != 0 as at n
= 1, path difference shall become 0 which is true for constructive
interference and not destructive interference]
f = 350(1 + 4*n)/0.34903032938*8
f = 125.34727305( 1 + 4n)
three lowest frequencies for destructive interference at point P
are
f1 = 626.736365 Hz
f2 = 1629.514549 Hz
f3 = 2632.29273407 Hz