Question

Write a RIMS-compatible C-language for-loop that counts the number of times a bit of A is followed by a bit of the opposite parity (01 or 10) and writes the value to B. For example 00100110 has 4 cases: 00100110, 00100110, 00100110, 00100110.

Answer 1

#include <stdio.h>

int main() {

    // your code goes here

    printf("Enter number of digits in number: ");

    int size;

    scanf("%d",&size);

    printf("\n");

    int A[size];

    printf("Enter the digits in number one by one: ");

    for(int i=0;i<size;i++)

    {

        scanf("%d",&A[i]);

        

    }

    

    int B=0; //counts number of 01 or 10 occurences

    for(int i=0;i<size-1;i++)

    {

        if((A[i]==0&&A[i+1]==1)||(A[i]==1&&A[i+1]==0))

            B++;

    }

    

    printf("\n");

    printf("The number of occurences of 01 or 10 in given number is: ");

    printf("%d", B);

    return 0;

    

}