Question

Write a C program that counts the number of odd numbers with using function count() within the set. The set has only one negative number which determines the end of set.

Answer 1

#include <stdio.h>
#include <ctype.h>
#include <math.h>
using namespace std;
int count(int set[])
{
   int a, num = 0, i;
   for (i = 0; i != -1; i++)
   {
       a = set[i] % 2;
       if (a = !0)
           num++;
   }
   return num;
}
int main()
{
   int i,set[] = { 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,-1 };
   cout << "total elements in set are";
   for (i = 0; set[i] != -1; i++)
   {
       cout << set[i]<<endl;
   }

   cout <<endl<< "Total odd numbers in set is: "<<count(set);
   system("pause");
   return 0;
}

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