Question

Write a C program that counts the number of repeated characters in a phrase entered by the user and prints them.

If none of the characters are repeated, then print “No character is repeated”

For example:

If the phrase is “full proof” then the output will be Number of characters repeated: 3 Characters repeated: f, l, o Note: Assume the length of the string is 10.

###Note: the output should print exactly as it is stated in the example if the user enters "full proof" ###

Answer 1

Code:

#include<stdio.h>
#include<string.h>
int main()
{
   char phrase[100],duplicate[100];
   int count=0,yes=0,i,j,k;
   printf("Enter a phrase:");
   gets(phrase);/*Reading user input*/
   for(i=0;phrase[i]!='\0';i++)
   {/*This loop iterates for every charecter*/
       if(phrase[i]==' ')
       {/*If space is present then we skip comparing*/
           continue;
       }
      
       for(j=i+1;phrase[j]!='\0';j++)
       {/*This loop iterates for phrase[i+1] to untill phrase[j]=="\0"*/
          
           if(phrase[i]==phrase[j])
           {/*IF phrase[i]==phrase[j]*/
               yes=0;
               for(k=0;k<count;k++)
               {
                   if(duplicate[k]==phrase[i])
                   {/*If the charecter alredy present in the duplicate array*/
                       yes=1;
                   }
               }
               if(!yes)
               {/*If charecter is not present in the array
               then we add it to the duplicate array*/
                   duplicate[count]=phrase[i];
                   count++;
                   /*Here we increase the count*/
               }
           }
       }
   }
   if(count==0)
   {/*if count is 0 then we print no duplicates*/
       printf("No duplicates");
   }
   else
   {/*Else we print the no of duplicates and duplicate charecters*/
       printf("Number of Charecters Repeated:%d ",count);
       printf("Charecters repeated: ");
       for(i=0;i<count;i++)
       {
           if(i!=count-1)
           {
               printf("%c,",duplicate[i]);
           }
           else
           {
               printf("%c",duplicate[i]);  
           }
          
       }
   }
}

Output:

Indentation: